You have to divide denominator by numerator to find the constant of proportionality.
Answer:
x = 4
Step-by-step explanation:
If you have any questions about the way I solved it, don't hesitate to ask me in the comments below
P.s: I used the Law of Sines, but there are many other ways to solve it
A googol is 1.0*10^100. there are <span>25000000000 RBC in the average adult.
The number of adults equals
1.0*10^100 / </span><span>25000000000
=</span>400000000000000000000000000000000000000000000000000000000000000000000000000000000000000000
(=10^100/(25*10^9)=4*10^89)
Answer:
112
Step-by-step explanation:
Just solve it easy peasy
![7[(25+9)-3(2-1)]](https://tex.z-dn.net/?f=7%5B%2825%2B9%29-3%282-1%29%5D)
First solve the inner brackets
![7[(34)-3(3)]\\7[25-9]](https://tex.z-dn.net/?f=7%5B%2834%29-3%283%29%5D%5C%5C7%5B25-9%5D)
Now the other brackets
![7[25-9]\\7[16]\\112](https://tex.z-dn.net/?f=7%5B25-9%5D%5C%5C7%5B16%5D%5C%5C112)
Answer:
The minimum score needed to be considered for admission to Stanfords graduate school is 328.48.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the minimum score needed to be considered for admission to Stanfords graduate school?
Top 2.5%.
So X when Z has a pvalue of 1-0.025 = 0.975. So X when Z = 1.96




The minimum score needed to be considered for admission to Stanfords graduate school is 328.48.