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3 years ago

Help me please please please PLEASE! NO LINKS

Mathematics

2 answers:

Deffense [45]3 years ago

8 0

They got it right above ^

tresset_1 [31]3 years ago

7 0

Answer:

for the first one its right one down 4

for the second one its right 4 down 1

for the last one its left 1 up 4

im pretty sure i helped u with your other one too

hope this helps

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at the center of a circular pond, there is apole of 11.63 high above the surface of water from a point on the edge of aponf , a

Sonbull [250]

Answer:

Step-by-step explanation:

I think its 2.....

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3 years ago

Which of the following is an equation of the circle with its center at (0,0) that passes through (3,4) in the standard (x,y) coo

natka813 [3]

Answer: x² + y² = 25

Step-by-step explanation: As we have x²+y²=25 (A) as options,

x-y=1 (B)

x+y=25 (C)

x²+y²=5 (D)

We can rule out B and C as they are not circles. Circles must be

(x - xc)² + (y - yc)² = r². They must have index 2.

We have then A or D.

As the circle must pass through (3,4), we can substitute as x=3 and y=4

(A) 3² + 4² = 9 + 16 = 25 ok

(D) 3² + 4² = 9 + 16 = 25 ≠ 5

So, it is A, x² + y² = 25

4 0

3 years ago

How many solutions does this system have?

crimeas [40]

Answer:

-x+3y=9

i think this is answer

7 0

2 years ago

Chaz bought 4 baseball cards for $2 each and 8 baseball cards for $3 each. Simplify the expression to find the amount Chaz spent

Murljashka [212]

The answer you will get when you multiple and add is 32

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3 years ago

The lifespans of seals in a particular zoo are normally distributed. The average seal lives

Varvara68 [4.7K]

Answer:

2.5%

Step-by-step explanation:

It is given that:

lifespans of seals in a particular zoo are normally distributed. The average seal lives 13.8 years and the standard deviation is 3.2 years.

We want to use the empirical rule to estimate the probability of a seal living longer than 7.4

Let's calculate the z-score of 7.4 using

$z = \frac{x - \mu}{ \sigma}$

$z = \frac{7.4 - 13.8}{3.2}$

$z = - 2.00$

According to empirical rule, 95% of the distribution is within 2 standard deviations, i.e (-2 to 2)

So from (-2 to 0), we would have 47.5%

Since we are looking for the area to the left of -2.00 we subtract this from 50%

to get 2.5%

3 0

3 years ago

Read 2 more answers