The gas exerts a pressure of 218.75 kPa when its volume is reduced to 2.0 L, following the behavior of an ideal gas.
Ideal gas behavior:
Suppose the initial volume of carbon dioxide gas is V = 3.5l
Initial pressure is P = 125 kPa
Since the volume is reduced to 2.0l, the final volume is shown as V'= Will be done. 2L
The final pressure of the gas is P'.
We consider the behavior of gas to be ideal. From the ideal gas equation, it becomes as follows.
PV = P'V'
125 × 3.5 = P'× 2
P'= 218.75 kPa
Therefore, the final pressure is 218.5 kPa.
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You have the following expressions given in the problem above:
(y^2/y-3)(y^2-y-6/y^2+y)
By applying the exponents properties, you can simplify it, as it shown below:
(y^2/y-3)(y^2-y-6/y^2+y)
(y^4-y^3-6y^2)/(y^3+y^2-3y2-3y)
(y^4-y^3-6y^2)/(y^3-2y2-3y)
Then, you have:
y^2(y^2-y-6)/y(y^2-2y-3)
(y^2-y-6)/(y^2-2y-3)
The answer is: (y^2-y-6)/(y^2-2y-3)
2/8 has a greater capacity because 2/8 of a gallon is 4 cups. 4 > 7/8
Hope this helps!!
Answer:
JK and LM are equal because it tells us they are equal.
JL and LN are equal because L is the midpoint of JN.
Since they are both equal, sides LK and NM must be equal.
Step-by-step explanation:
Hope this helps!
