9514 1404 393
Answer:
- 2nd force: 99.91 lb
- resultant: 213.97 lb
Step-by-step explanation:
In the parallelogram shown, angle B is the supplement of angle DAB:
∠B = 180° -77°37' = 102°23'
Angle ACB is the difference of angles 77°37' and 27°8', so is 50°29'.
Now, we know the angles and one side of triangle ABC. We can use the law of sines to solve for the other two sides.
BC/sin(A) = AB/sin(C)
AD = BC = AB·sin(A)/sin(C) = (169 lb)sin(27°8')/sin(50°29') ≈ 99.91 lb
AC = AB·sin(B)/sin(C) = (169 lb)sin(102°23')/sin(50°29') ≈ 213.97 lb
Answer:
Mizuki here to answer! B is the correct answer!
Step-by-step explanation:
1 - 0.4 = 0.6
2.1 x 0.6 = 1.26
D. (8, -22) is the correct answer
The sixth graders collected $250 of their $300 goal. The seventh graders collected $250 of thier $450 goal.
Sixth Graders:
$250 / $300
Reduce: $25 / $30 = 5/6
Seventh Graders:
$250 / $450
Reduce: $25 / $45 = 5/9
Answer:
<h2>f(0) = -4</h2>
Step-by-step explanation:
