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Kruka [31]
2 years ago
11

What is the solution to the equation 5x+4=7

Mathematics
2 answers:
Amanda [17]2 years ago
5 0

Answer:

x = 3/5

Step-by-step explanation:

5x+4=7

Subtract 4 from each side

5x+4-4=7-4

5x = 3

Divide each side by 5

5x/5=3/5

x = 3/5

Orlov [11]2 years ago
3 0
X=3/5
do you need an explanation?
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Are you telling us? This doesn't sound like a question.
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3 regions are defined in the figure find the volume generated by rotating the given region about the specific line
anastassius [24]

The volume generated by rotating the given region R_{3} about OC is \frac{4}{g}  \pi

<h3>Washer method</h3>

Because the given region (R_{3}) has a look like a washer, we will apply the washer method to find the volume generated by rotating the given region about the specific line.

solution

We first find the value of x and y

y=2(x)^{\frac{1}{4} }

x=(\frac{y}{2} )^{4}

y=2x

x=\frac{y}{2}

\int\limits^a_b {\pi } \, (R_{o^{2} }  - R_{i^{2} } )       dy

R_{o} = x = \frac{y}{2}

R_{i} = x= (\frac{y}{2}) ^{4}

a=0, b=2

v= \int\limits^2_o {\pi } \, [(\frac{y}{2})^{2} - ((\frac{y}{2}) ^{4} )^{2} )  dy

v= \pi \int\limits^2_o= [\frac{y^{2} }{4} - \frac{y^{8} }{2^{8} }}  ] dy

v= \pi [\int\limits^2_o {\frac{y^{2} }{4} } \, dy - \int\limits^2_o {\frac{y}{2^{8} } ^{8} } \, dy ]

v=\pi [\frac{1}{4} \frac{y^{3} }{3}  \int\limits^2_0 - \frac{1}{2^{8} }  \frac{y^{g} }{g} \int\limits^2_o\\v= \pi [\frac{1}{12} (2^{3} -0)-\frac{1}{2^{8}*9 } (2^{g} -0)]\\v= \pi [\frac{2}{3} -\frac{2}{g} ]\\v= \frac{4}{g} \pi

A similar question about finding the volume generated by a given region is answered here: brainly.com/question/3455095

6 0
2 years ago
What is (x^4)/(x^0)?
e-lub [12.9K]

Answer:

x^2+4x

Step-by-step explanation:

Use the Foil formula

4 0
2 years ago
Rewrite f(x) = 2(x − 1)2 + 3 from vertex form to standard form. (2 points)
Ostrovityanka [42]

Answer:

F(x)= 4x-1 I think so hope it will help you

7 0
2 years ago
Does the table represent an exponential function? Explain.
Ede4ka [16]

Answer:

No, because as the x-values are increasing by a constant amount, the y-values are not being multiplied by a constant amount.

Step-by-step explanation:

We have a set of ordered pairs of the form (x, y)

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This means that:

\frac{y_2}{y_1}=\frac{y_3}{y_2}=\frac{y_4}{y_3}=by1y2=y2y3=y3y4=b

This is: y_2=by_1y2=by1

Now we have this set of points {(-1, -5), (0, -3), (1, -1), (2, 1)}

Observe that:

\begin{gathered}\frac{y_2}{y_1}=\frac{-3}{-5}=\frac{3}{5}\\\\\frac{y_3}{y_2}=\frac{-1}{-3}=\frac{1}{3}\\\\\frac{3}{5}\neq \frac{1}{3}\end{gathered}y1y2=−5−3=53y2y3=−3−1=3153=31

Then the values of y are not multiplied by a constant amount "b"

5 0
3 years ago
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