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3 years ago

Which fractions are equivalent to 1/5?

Mathematics

2 answers:

Nuetrik [128]3 years ago

7 0

Answer: B. 2/10 and C. 20/100

Step-by-step explanation: Have a nice day!✌️

Anit [1.1K]3 years ago

5 0

Answer:

2/10&20/100

Step-by-step explanation

hope it helps

please mark brainliest

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Please help me with this.

tatyana61 [14]

By understanding and applying the characteristics of <em>piecewise</em> functions, the results are listed below:

r (- 3) = 15
r (- 1) = 11
r (1) = - 7
r (5) = 13

<h3>How to evaluate a piecewise function at given values</h3>

In this question we have a <em>piecewise</em> function formed by three expressions associated with three respective intervals. We need to evaluate the expression at a value of the <em>respective</em> interval:

-3 ∈ (- ∞, -1]

r(- 3) = - 2 · (- 3) + 9

r (- 3) = 15

-1 ∈ (- ∞, -1]

r(- 1) = - 2 · (- 1) + 9

r (- 1) = 11

1 ∈ (-1, 5)

r(1) = 2 · 1² - 4 · 1 - 5

r (1) = - 7

5 ∈ [5, + ∞)

r(5) = 4 · 5 - 7

r (5) = 13

By understanding and applying the characteristics of <em>piecewise</em> functions, the results are listed below:

r (- 3) = 15
r (- 1) = 11
r (1) = - 7
r (5) = 13

To learn more on piecewise functions: brainly.com/question/12561612

#SPJ1

7 0

2 years ago

The school cafeteria surveyed students to see what their favorite lunch is, and the

Sergio039 [100]

Answer:

40%

Step-by-step explanation:

Degree representing students who prefer burgers = 144°

Percentage of students who like burger = $\frac{144}{360} \times 100$

$= 0.4 \times 100$

$= 40 percent$

Percentage of students who offered burger = 40%

3 0

3 years ago

What are the next three terms in these 2 sequences?<br><br> 1. 3, 8, 23, 68<br><br> 2. 2, 6, 18

Karolina [17]

1:
3*3=8 ;
8*3=23
23*3=68
68*3=204
1.3,8,23,68,204 ...

2.
2*3=6
6*3=18
18*3=54
2, 6,18,54

multiply all on 3)

3 0

3 years ago

Perímetro de un trapecio isosceles es 110 m, las bases miden 40 y 30 respectivamente.

Fantom [35]

Answer: English please

Step-by-step explanation:

8 0

3 years ago

A pen company averages 1.2 defective pens per carton produced (200 pens). The number of defects per carton is Poisson distribute

nlexa [21]

Answer:

a. P(x = 0 | λ = 1.2) = 0.301

b. P(x ≥ 8 | λ = 1.2) = 0.000

c. P(x > 5 | λ = 1.2) = 0.002

Step-by-step explanation:

If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

$P(k)=\frac{\lambda^{k}e^{-\lambda}}{k!}= \frac{1.2^{k}\cdot e^{-1.2}}{k!}$

a. What is the probability of selecting a carton and finding no defective pens?

This happens for k=0, so the probability is:

$P(0)=\frac{1.2^{0}\cdot e^{-1.2}}{0!}=e^{-1.2}=0.301$

b. What is the probability of finding eight or more defective pens in a carton?

This can be calculated as one minus the probablity of having 7 or less defective pens.

$P(k\geq8)=1-P(k$

$P(0)=1.2^{0} \cdot e^{-1.2}/0!=1*0.3012/1=0.301\\\\P(1)=1.2^{1} \cdot e^{-1.2}/1!=1*0.3012/1=0.361\\\\P(2)=1.2^{2} \cdot e^{-1.2}/2!=1*0.3012/2=0.217\\\\P(3)=1.2^{3} \cdot e^{-1.2}/3!=2*0.3012/6=0.087\\\\P(4)=1.2^{4} \cdot e^{-1.2}/4!=2*0.3012/24=0.026\\\\P(5)=1.2^{5} \cdot e^{-1.2}/5!=2*0.3012/120=0.006\\\\P(6)=1.2^{6} \cdot e^{-1.2}/6!=3*0.3012/720=0.001\\\\P(7)=1.2^{7} \cdot e^{-1.2}/7!=4*0.3012/5040=0\\\\$

$P(k$

c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?

We can calculate this as we did the previous question, but for k=5.

$P(k>5)=1-P(k\leq5)=1-\sum_{k=0}^5P(k)\\\\P(k>5)=1-(0.301+0.361+0.217+0.087+0.026+0.006)\\\\P(k>5)=1-0.998=0.002$

5 0

3 years ago