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Masja [62]
3 years ago
15

HELPPP!!!! Both questions are incredibly confusing to me !!!!!

Mathematics
1 answer:
Darya [45]3 years ago
7 0

Answer:

Step-by-step explanation:

I'm going to start with problem 3. You need to become familar with the kind of tricks teachers play on you.

Problem 3 depends on getting RS = RW.

RT = RT                                    Reflexive property

<STR = <WTR                           A straight line having 1 rt angle  actually has 2

ST = TU                                    They are marked as equal

Triangle STR=Triangle WTR    SAS

RS = RW                                    Corresponding parts of = triangles are =

8x = 6x + 5                                Subtract 6x from both sides

8x -6x = 6x - 6x + 5                   Combine

2x = 5                                         Divide by 2

2x/2 = 5/2

x = 2.5

RU = 6*2.5 + 5

RU = 15 + 5

RU = 20

Now we can play with Question 4.

This question depends on the method used in three, although not entirely.

What you need to know is that W is on RT when you take a ruler and make RT longer. You can put W anywhere as long as it is on RT when it is made longer.

Directions

Make RT longer. Draw down and to your right.

Put a point anywhere on the length starting at T. Label this new point as W. There's your W. It goes anywhere on the part of RT made longer.

Draw UW.

Label UW as 8

Now draw another line from S to W. Guess what? By the methods used in question 3, it's also 8. So SW = 8

TW = TW                        Reflexive

<UTW = STW                 Same reason as in 3. UtW is a right angle

UT = ST                          Given (the marking tells you so.

ΔUTW = ΔSTW              SAS

UW = SW                       Corresponding parts of = triangles are =

SW  = 8

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Answer:

Brandon

Step-by-step explanation:

GIVEN: Branden and Pete each play running back. Branden carries the ball 75 times for  550 yards, and Pete has 42 carries for 380 yards.

TO FIND: Who runs farther per carry.

SOLUTION:

Total yards traveled by Brandon =550\text{yards}

No. of times ball carried by Brandon =75\text{ times}

Average yards per carry for Brandon =\frac{\text{total yards traveled}}{\text{number of times ball carried}}

                                                              =\frac{550}{75}

                                                              =\frac{22}{3}\text{ yards per carry}

                                                              =7.33\text{ yards per carry}

Total yards traveled by Pete =380\text{ yards}

No. of times ball carried by Pete =42\text{ times}

Average yards per carry for Pete =\frac{\text{total yards traveled}}{\text{number of times ball carried}}

                                                       =\frac{380}{42}

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Answer:

see below

Step-by-step explanation:

butterfly = x minutes

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Part B

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x+ (x+20) = 50

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2x+20-20 = 50-20

2x = 30

2x/2 = 30/2

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Part C

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We only have a total of 50 minutes

50-45 = 5

But he spend more time on the breast stroke ( 20 minutes more), but if he spend 45 minutes on the butterfly, he would have to spend less on the breast stroke.

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<u><em>function </em></u>: p(x) = 65 + 25(x)

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