Answer:
The pvalue of 0.0113 < 0.05 means that there is sufficient evidence to conclude that the mean time to find another position is less than 28 weeks at the 5% level of significance
Step-by-step explanation:
The null hypothesis is:

The alternate hypotesis is:

The test statistic is:

In which X is the sample mean,
is the value tested at the null hypothesis,
is the standard deviation and n is the size of the sample.
A recent survey of 50 executives who were laid off during a recent recession revealed it took a mean of 26 weeks for them to find another position.
This means that 
Assume the population standard deviation is 6.2 weeks.
This means that 
Does the data provide sufficient evidence to conclude that the mean time to find another position is less than 28 weeks at the 5% level of significance
We have to find the pvalue of Z, looking at the z-table, when
. It if is lower than 0.05, it provides evidence.



has a pvalue of 0.0113 < 0.05.
The pvalue of 0.0113 < 0.05 means that there is sufficient evidence to conclude that the mean time to find another position is less than 28 weeks at the 5% level of significance
S A = r² π + 2 r π h
192 π = r² π + 2 r π h / : π
192 = r² + 2 r h
2 r h = 192 - r²
h = (192 - r² ) / 2 r
V = r² π h = r² π ( (192 - r² ) / 2 r ) =
= π / 2 ( 192 r - r³ )
Answer:
Inverse property
Step-by-step explanation:
First we define the variables:
m = multiple choice questions
s = short answer questions
Next we need to satisfy 2 conditions:
1) There are a total of 40 questions. We can represent this mathematically using the variables I defined:

2) The multiple-choice questions are worth 2 points and the short-answer are worth 4 points but they need to total 100 points. This can also be represented mathematically:

By satisfying the conditions provided we were able to create the 2 equations!


Answer:
49/1
Step-by-step explanation:
The point is on (1,49)