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klio [65]
2 years ago
9

The following are perfect cube terms, except

Mathematics
1 answer:
natima [27]2 years ago
7 0

Answer:

ugh we're r

the cubes lolllll

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(7 - 3t) + 3(-2t + 5)
katrin2010 [14]

Answer:

22-9t

Step-by-step explanation:

(7 - 3t) + 3(-2t + 5)

=

7+−3t+(3)(−2t)+(3)(5)=

7+−3t+−6t+15

=

Now you need to combine like terms.

7+−3t+−6t+15

=

(−3t+−6t)+(7+15)=

-9t+22=

22-9t

There you go.

6 0
3 years ago
Read 2 more answers
Help it’s due soon!
xz_007 [3.2K]

Answer:

25%

Step-by-step explanation:

5 0
2 years ago
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7x + y = 13<br> 4x – 4y = -20
aalyn [17]

Answer: (x,y) = (1,6)

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
In how many ways can a
Tomtit [17]

Answer:

The answer is 364. There are 364 ways of choosing a recorder, a facilitator and a questioner froma club containing 14 members.

This is a Combination problem.  

Combination is a branch of mathematics that deals with the problem relating to the number of iterations which allows one to select a sample of elements which we can term "<em>r</em>" from a collection or a group of distinct objects which we can name "<em>n</em>". The rules here are that replacements are not allowed and sample elements may be chosen in any order.

Step-by-step explanation:

Step I

The formula is given as

C (n,r) = \frac{n}{r} = \frac{n!}{(r!(n-r)!)}

n (objects) = 14

r (sample) = 3

Step 2 - Insert Figures

C (14, 3) = (\frac{14}{3}) = \frac{14!}{(3!(14-3)!)}

= \frac{87178291200}{(6 X 39916800)}

= \frac{87178291200}{239500800}

= 364

Step 3

The total number of ways a recorder, a facilitator and a questioner can be chosen in a club containing 14 members therefore is 364.

Cheers!

6 0
3 years ago
Karen's penny bank is
galina1969 [7]
The answer is 532 full your welcome yay fun
6 0
2 years ago
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