Answer:
9 years old.
Step-by-step explanation:
Since the ages of all of these students are being represented in relation to the middle student's age then we can create formulas for each student and then apply them to the formula for the sum of their ages and solve for the middle child's age (M) like so... (oldest child's age is represented by variable O and youngest child's age is represented by variable Y)
O = M + 6
Y = M - 3
30 = (M+6) + M + (M-3) ... combine like terms
30 = 3M + 3 ... subtract 3 from both sides
27 = 3M ... divide both sides by 3
9 = M
Now we know that the middle child is 9 years old.
The answer is 25
1/5 of 45 is 9, so you have 36 tickets
then half of 36 is 18
then you add the 7 tickets Danny won
18+7=25
Answer:
3/2 < x < 2
Step-by-step explanation:
We assume the problem is ...
[tek]\dfrac{1}{x-2}<-2[/tex]
This will not be true for x-2 > 0 because that would make the left side positive. So, we must have x < 2, which makes the denominator negative. Multiplying by (x-2), we get ...
1 > -2(x -2)
1 > -2x +4
2x > 3 . . . . . . add 2x-1
x > 3/2
From above, we also have x < 2, so the solution set is ...
3/2 < x < 2
Basically it means judging if something is right.
let the greatest number be a and remainder be x. And let the whole number result of the division be b, c and d. So we have
ab + x = 2447............(1)
ac + x = 3118...............(2)
ad + x = 6168.............(3)
Subtracting (2) - (1) gives:-
ac - ab = 671
a(c - b) =671
Now 671 = 61 * 11 so 61 could be the value of a
Checking:- 2447 / 61 = 40 remainder 7 , 3118 / 61 = 51 remainder 7
and 6168 / 61 = 101 remainder 7
Answer 61
