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nikklg [1K]
4 years ago
7

What is the solution set of [1/x-2]<-2

Mathematics
1 answer:
BigorU [14]4 years ago
7 0

Answer:

  3/2 < x < 2

Step-by-step explanation:

We assume the problem is ...

  [tek]\dfrac{1}{x-2}<-2[/tex]

This will not be true for x-2 > 0 because that would make the left side positive. So, we must have x < 2, which makes the denominator negative. Multiplying by (x-2), we get ...

  1 > -2(x -2)

  1 > -2x +4

  2x > 3 . . . . . . add 2x-1

  x > 3/2

From above, we also have x < 2, so the solution set is ...

  3/2 < x < 2

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9. If LK MK, LK = 7x - 10, KN = x + 3, MN = 9x - 11, and KJ = 28, find LJ.
olasank [31]

Answer:

LJ = 46

Step-by-step explanation:

Given:

LK = MK

LK = 7x - 10

KN = x + 3

MN = 9x - 11

KJ = 28

Required:

LJ

Solution:

Step 1: create an equation to find the value of x

Since we are given that LK = MK, and LK = 7x - 10, let's find the expression for MK to get an equation.

MK + KN = MN (segment addition postulate)

MK = MN - KN (Subtract KN from each side)

MK = (9x - 11) - (x + 3) (subtitution)

MK = 9x - 11 - x - 3

MK = 9x - x - 11 - 3

MK = 8x - 14

LK = MK, therefore,

7x - 10 = 8x - 14

Subtract 8x from each side

7x - 10 - 8x = 8x - 14 - 8x

-x - 10 = -14

Add 10 to both sides of the equation

-x - 10 + 10 = -14 + 10

-x = -4

Divide both sides by -1

x = 4

Step 2: Find LJ

LJ = LK + KJ (segment addition postulate)

LJ = (7x - 10) + (28)

Plug in the value of x

LJ = 7(4) - 10 + 28

LJ = 28 - 10 + 28

LJ = 46

7 0
4 years ago
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