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nikklg [1K]
4 years ago
7

What is the solution set of [1/x-2]<-2

Mathematics
1 answer:
BigorU [14]4 years ago
7 0

Answer:

  3/2 < x < 2

Step-by-step explanation:

We assume the problem is ...

  [tek]\dfrac{1}{x-2}<-2[/tex]

This will not be true for x-2 > 0 because that would make the left side positive. So, we must have x < 2, which makes the denominator negative. Multiplying by (x-2), we get ...

  1 > -2(x -2)

  1 > -2x +4

  2x > 3 . . . . . . add 2x-1

  x > 3/2

From above, we also have x < 2, so the solution set is ...

  3/2 < x < 2

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<em>here's</em><em> your</em><em> solution</em>

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<em>=</em><em>></em><em> </em><em>putting</em><em> the</em><em> value</em><em> of</em><em> </em><em>radius</em><em> and</em><em> height</em><em> </em>

<em>=</em><em>></em><em> </em><em> </em><em> </em><em>volume</em><em> </em><em>=</em><em> </em><em>1</em><em>0</em><em>^</em><em>2</em><em>*</em><em>2</em><em>0</em><em>/</em><em>3</em><em>π</em>

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<em>hope</em><em> it</em><em> helps</em>

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