2 years ago

What is the slope of the line passing through the points (-3, 4) and (2, - 1)?

Mathematics

1 answer:

12345 [234]2 years ago

3 0

Answer:

-1

Step-by-step explanation:

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Would the product change if 50 + 2 on the top of the area model was changed to 20 + 30 + 2? Explain

ollegr [7]

Answer:

It would not change

Step-by-step explanation:

Because if you add you get the same thing

4 0

3 years ago

A triangle with vertices at A(0, 0), B(0, 4), and C(6, 0) is dilated to yield a triangle with vertices at A′(0, 0), B′(0, 10), a

sineoko [7]

ANSWER

The scale factor is
$2.5$

EXPLANATION

The given triangle has vertices,

$A(0,0),B(0,4),\:and\:C(6, 0)$ .

The vertices of the image triangle is,

$A'(0,0),B'(0,10),\:and\:C'(15, 0)$ .

The scale factor is given by

$k = \frac{image \: length}{object \: length}$

So we can use any of the corresponding sides to determine the scale factor,

$k = \frac{|A'B'|}{ |AB|}$

$k = \frac{ |10 - 0| }{ |4 - 0|}$

$k = \frac{ |10| }{ |4 |} = \frac{10}{4} = 2.5$

Or

$k = \frac{|A'C'|}{ |AC|}$

$k = \frac{ |15 - 0| }{ |6 - 0|}$

$k = \frac{ |15| }{ |6|} = \frac{15}{6} = 2.5$

Or

$k=\frac{|B'C'|}{|BC|}$

$k = \frac{\sqrt{(15 - 0)^2+(0-10)^2 }}{\sqrt{(6 - 0)^2+(0-4)^2}}$

$k = \frac{ 5\sqrt{13}}{2\sqrt{13}} = \frac{5}{2} = 2.5$

The correct answer is C

3 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B5%7D%7B8%7D%20%20%5Ctimes%204" id="TexFormula1" title=" \frac{5}{8} \times 4" al

Vsevolod [243]

Answer:

The result is

$\frac{5}{2}$