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2 years ago

What is the total number of possible four-card poker hands if the hand contains exactly one heart?

Mathematics

1 answer:

lesantik [10]2 years ago

4 0

Answer:

Step-by-step explanation:

Assuming no wild cards ie. 52 card deck.

13 ways to fill the heart card

39 ways to fill the second card

38 ways to fill the third card

37 ways to fill the fourth card

13(39)(38)(37) = 712,842

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A box of 20 dvds is worth $240.00 the box contains some DVDs worth $12.00 each and some DVDs worth 16.00 each. Which system of e

Advocard [28]

Answer:

Step-by-step explanation:

8 0

3 years ago

Find the solution of the given initial value problem. ty' + 2y = sin t, y π 2 = 9, t > 0 y(t) =

Helen [10]

For the ODE

$ty'+2y=\sin t$

multiply both sides by t so that the left side can be condensed into the derivative of a product:

$t^2y'+2ty=t\sin t$

$\implies(t^2y)'=t\sin t$

Integrate both sides with respect to t :

$t^2y=\displaystyle\int t\sin t\,\mathrm dt=\sin t-t\cos t+C$

Divide both sides by $t^2$ to solve for y :

$y(t)=\dfrac{\sin t}{t^2}-\dfrac{\cos t}t+\dfrac C{t^2}$

Now use the initial condition to solve for C :

$y\left(\dfrac\pi2\right)=9\implies9=\dfrac{\sin\frac\pi2}{\frac{\pi^2}4}-\dfrac{\cos\frac\pi2}{\frac\pi2}+\dfrac C{\frac{\pi^2}4}$

$\implies9=\dfrac4{\pi^2}(1+C)$

$\implies C=\dfrac{9\pi^2}4-1$

So the particular solution to the IVP is

$y(t)=\dfrac{\sin t}{t^2}-\dfrac{\cos t}t+\dfrac{\frac{9\pi^2}4-1}{t^2}$

$y(t)=\dfrac{4\sin t-4t\cos t+9\pi^2-4}{4t^2}$

6 0

2 years ago

Convert to a percent: 3.33 3/5

Free_Kalibri [48]

3.33=333%
and
3/5=.6=60%
to find a percent find a decimal and move the decimal point two spaces right

7 0

3 years ago

Round to the hundredth 8.2548

finlep [7]

Answer:

8.25

Step-by-step explanation:

6 0

2 years ago

Find the slope of the line passing through each of the following pairs of points.

boyakko [2]

If you start at (-3,1) and end up at (0,3), you will have increased x by 3 and y by 2. Thus, the slope of this line is m = rise / run = 3 / 2.

Using the point-slope form of the equation of a straight line, we get:

y - 1 = (3/2)(x+3).

This could be rewritten in other forms:

y = 1 + (3/2)x + 9/2, or y = 2/2 + (3/2)x + 9/2, or y = (3/2)x + 11/2.

6 0

3 years ago

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