Answer:
The total surface area of this square pyramid is 
Step-by-step explanation:
we know that
The surface area of a square pyramid is equal to
![SA=b^{2} +4[\frac{1}{2}(b)(h)]](https://tex.z-dn.net/?f=SA%3Db%5E%7B2%7D%20%2B4%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28h%29%5D)
we have
----> the length side of the square base
----> the height of the triangular faces
substitute the values
![SA=9^{2} +4[\frac{1}{2}(9)(12)]=297\ mm^{2}](https://tex.z-dn.net/?f=SA%3D9%5E%7B2%7D%20%2B4%5B%5Cfrac%7B1%7D%7B2%7D%289%29%2812%29%5D%3D297%5C%20mm%5E%7B2%7D)
Answer:
Answer is 32
Step-by-step explanation:
Mode = no of stu +1/2
Mode =12+1/2
Mode =13/28=6.5
Mode =6th mark +7th mark /2
Mode=32+32/2
Mode=64/2
Mode=32
Hope it helps
Peace
Please mark me as brainliest
First you'll have to bring the equation in form y = mx + b.
4y = -x - 32
y = -1/4 x - 8
So the slope is -1/4 and y-intercept is -8
Hope this helps :)
Answer:
9
Step-by-step explanation:
6÷2(1+2)
(1+2)
3
6÷2×3
6÷2=
3
3×3
9
