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ivann1987 [24]
3 years ago
6

Shana bought sodas and popcorn for the movies .Sodas cost $3 each and popcorn cost $4 per bag . Shana bought 7 things from the c

oncession., all either sodas or bags of popcorn. Shana spent a total of $26 . Write a system of equations involving the number of sodas S ,and the bags of popcorn ,B .Solve the system to see how many of each shana bought
Mathematics
1 answer:
asambeis [7]3 years ago
3 0

Answer: Shana bought 2 sodas.

Shana bought 5 bags of popcorn.

Step-by-step explanation:

Let S represent the number of sodas that Shana bought.

Let B represent the number of bags of popcorn that Shana bought.

Shana bought 7 things from the concession., all either sodas or bags of popcorn. This means that

S + B = 7

Sodas cost $3 each and popcorn cost $4 per bag. Shana spent a total of $26. This means that

3S + 4B = 26 - - - - - - - - - - - - -1

Substituting S = 7 - B into equation 1, it becomes

3(7 - B) + 4B = 26

21 - 3B + 4B = 26

- 3B + 4B = 26 - 21

B = 5

S = 7 - B = 7 - 5

S = 2

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\sf\dfrac{4}{7}\times\dfrac{1}{4}\rightarrow\dfrac{4\times 1}{7\times 4}\rightarrow\dfrac{4}{28}\rightarrow\dfrac{1}{7}

\sf\dfrac{4}{7}\times\dfrac{1}{6}\rightarrow\dfrac{4\times 1}{7\times 6}\rightarrow\dfrac{4}{42}\rightarrow\dfrac{2}{21}

To find out which one is bigger, we need a common denominator. The LCM of 7 and 21 is 21, so convert the first fraction into a denominator of 21. 7 goes into 21 three times, multiply this to the numerator and denominator:

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