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Shkiper50 [21]
3 years ago
15

A particular plant root grows 3.5 inches per month.How many centimeters is the plant growing each month?

Mathematics
2 answers:
STALIN [3.7K]3 years ago
5 0

Answer:1 inch = 2.54 centimeters so the answer is 3.76

Step-by-step explanation:

(1 inch = 2.54 centimeters). 0.73 centimeters 1.38 centimeters 6.04 centimeters 8.89 centimeters unsubscribe · report · tue mathematics

Sliva [168]3 years ago
5 0
The answer is 8.89 centimeters
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I need help i’m failing math!!!
adell [148]

Answer:

\huge\boxed{\bf\:2\sqrt{5} \:\: units }

Step-by-step explanation:

We have a figure given in the shape of a square with a diagonal (x) passing from one edge to another. We need to find the measure of its diagonal if the side of the square is \sqrt{10} units.

We know that, a square has all equal sides. Then, all the sides of the square will be equal to \sqrt{10} units.

Now, let's find the diagonal.

To find the diagonal of a sqaure from one of its sides, we need to know the formula ⟶ Diagonal = side \bf\:\sqrt{2}.

By using this formula,

Diagonal (x)\\= side *\sqrt{2} \\= \sqrt{10} *\sqrt{2}\\ = \sqrt{5*2*2} \\= \boxed{\bf\:2\sqrt{5} \:units}

→ The diagonal of the square = 2√5 units.

\rule{150pt}{2pt}

5 0
3 years ago
A diver was 40 feet below the surface of the water. A fisherman was casting off a dock right above the diver that was 12 feet ab
Nesterboy [21]

Answer:

The answer is D.

Step-by-step explanation:

It is D because they cannot be negative feet away and if the fisherman is 12ft above water and the diver is 40ft below than 40 + 12 = 52. Hope this helps.

5 0
3 years ago
In triangle ABC, angle A=50°, angle C=65°. Point F is on AC such that, BF is perpendicular to AC. D is a point on BF (extended)
LiRa [457]

Answer:

The length of EF is 5.29

Step-by-step explanation:

If BC = 12 then;

FB = 12 × sin65 = 10.876

BA = FB/(sin50) = 10.876/(sin50) = 14.2

BD = AB (Sides of isosceles triangle) = 14.2

∴ DF = BD + FB = 10.876 + 14.2 = 25.07

∠F C D = tan⁻¹(D F/F C) =  tan⁻¹(25.07/(12×cos65)) = 78.6

∠F A D = tan⁻¹(D F/A F) =  tan⁻¹(25.07/(14.2×cos50)) = 70

∴ ∠D = 180 - (78.6° + 70°) = 31.4°

AE = AD × sin31.4° = 2×AB×cos(70° - 50°) × sin31.4

∴ AE =  2×14.2×cos(20°) × sin31.4 = 13.92

EC = AC × cos78.6° = (AB×cos50 + BC×cos65)×cos78.6° = 2.815

Therefore, from cosine rule, a² = b² + c² - 2·b·c × cos(A)

Hence, we have;

EF² = EC² + FC² - 2 × EC × FC ×cos∠FCD (Cosine rule)

That is, EF² = 2.815² + (12×cos65)² - 2 × 2.815× (12×cos65) ×cos78.6°

EF² = 27.98

∴EF = √27.98 = 5.29.

4 0
3 years ago
Using the box-and-whisker plot shown, find the quartile values Q1 and Q3
astra-53 [7]

Answer:

see explanation

Step-by-step explanation:

The lower quartile Q_{1} is positioned at the left side of the box, that is

Q_{1} = - 4

The upper quartile Q_{3} is positioned at the right side of the box

Q_{3} = 6

7 0
4 years ago
X / 3 - (x+5) / 5 = 7
Nastasia [14]

Answer:

x= 60

Explanation:

7 0
3 years ago
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