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yaroslaw [1]
3 years ago
10

-6-3 -5-5 7-7 -75-(-75) Thanks you. xo Anna

Mathematics
1 answer:
suter [353]3 years ago
8 0
-6-3= -9
-5-5= -10
7-7=0
-75-(-75)= 0
The last one is 0 because when you subtract a negative number it turns into addition. So -75 plus 75 which is 0
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Options other than A are B, C, and D are incorrect because the passage specifically states that Nawab's new motorcycle resulted in "the disgust of the ranchers", not happiness. their happiness (option B), their jealousy (option C) or their indifference (option D). The passage is therefore given that the managers of the farm reacted to Nawab's receipt of a motorcycle with disgust.

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Sam says 90 ÷ (–9) = 10. Is he correct? Use the drop–down menus to explain your answer.
SashulF [63]

Answer:

No.

Step-by-step explanation:

Sam is incorrect because if you look at the original problem, you'll see that he has missed the negative sign!

90 / 9 does equal 10, but 90 / -9 equals -10.

The only way to get a positive answer is if both the divisor and dividend are positive or if they are both negative.

Thus, the correct answer should be -10.

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3 years ago
Which expression is equivalent to 364ab7c9?​
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3 years ago
3. The curve C with equation y=f(x) is such that, dy/dx = 3x^2 + 4x +k
Andreas93 [3]

a. Given that y = f(x) and f(0) = -2, by the fundamental theorem of calculus we have

\displaystyle \frac{dy}{dx} = 3x^2 + 4x + k \implies y = f(0) + \int_0^x (3t^2+4t+k) \, dt

Evaluate the integral to solve for y :

\displaystyle y = -2 + \int_0^x (3t^2+4t+k) \, dt

\displaystyle y = -2 + (t^3+2t^2+kt)\bigg|_0^x

\displaystyle y = x^3+2x^2+kx - 2

Use the other known value, f(2) = 18, to solve for k :

18 = 2^3 + 2\times2^2+2k - 2 \implies \boxed{k = 2}

Then the curve C has equation

\boxed{y = x^3 + 2x^2 + 2x - 2}

b. Any tangent to the curve C at a point (a, f(a)) has slope equal to the derivative of y at that point:

\dfrac{dy}{dx}\bigg|_{x=a} = 3a^2 + 4a + 2

The slope of the given tangent line y=x-2 is 1. Solve for a :

3a^2 + 4a + 2 = 1 \implies 3a^2 + 4a + 1 = (3a+1)(a+1)=0 \implies a = -\dfrac13 \text{ or }a = -1

so we know there exists a tangent to C with slope 1. When x = -1/3, we have y = f(-1/3) = -67/27; when x = -1, we have y = f(-1) = -3. This means the tangent line must meet C at either (-1/3, -67/27) or (-1, -3).

Decide which of these points is correct:

x - 2 = x^3 + 2x^2 + 2x - 2 \implies x^3 + 2x^2 + x = x(x+1)^2=0 \implies x=0 \text{ or } x = -1

So, the point of contact between the tangent line and C is (-1, -3).

7 0
2 years ago
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