Answer:

Step-by-step explanation:
Let
h(t) ---> the height of an object in meters
t ----> the time in seconds
we have

For t=6 sec
substitute in the quadratic equation the value of t and solve for h


Answer: x = 15, ∠K = 45.7°, ∠L = 45.7°, ∠M = 88.6°
<u>Step-by-step explanation:</u>
Since ∠K ≅ ∠L, then ΔKLM is an isoceles triangle with base KL
KM ≅ LM
3x + 23 = 7x - 37
23 = 4x - 37
60 = 4x
15 = x
KM = LM = 3x + 23
= 3(15) + 23
= 45 + 23
= 68
KL = 9x - 40
= 9(15) - 40
= 135 - 40
= 95
Next, draw a perpendicular bisector KN from K to KL. Thus, N is the midpoint of KL and ΔMNL is a right triangle.
- Since N is the midpoint of KL and KL = 95, then NL = 47.5
- Since ∠N is 90°, then NL is adjacent to ∠l and ML is the hypotenuse
Use trig to solve for ∠L (which equals ∠K):
cos ∠L = 
cos ∠L = 
∠L = cos⁻¹ 
∠L = 45.7
Triangle sum Theorem:
∠K + ∠L + ∠M = 180°
45.7 + 45.7 + ∠M = 180
91.4 + ∠M = 180
∠M = 88.6
M<J = m<N ( alternate angles)
m<K = m<M ( alternate angles)
so the third angles must also be equal ( total 180 degrees in each triangle)
Therefor the triangles are similar
Step-by-step explanation:
when the difference between CI and SI given then the sum =
difference (100/r)^2
given difference is Rs . 180
Rate of interest is 15%
sum = 180× (100/15)^2
180×10000/225
= 8000