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Keith_Richards [23]
2 years ago
15

What is 122°F in °C?a.1 °Cb.10 °Cc.100 °Cd.110 °C​

Mathematics
2 answers:
frutty [35]2 years ago
8 0

Answer:

<h2>50° C</h2>

Step-by-step explanation:

<h2>By the Formula :-</h2>

= > (122°F − 32) × 5/9

= > 50°C...ans

<h2>Hope it Helps you!!</h2>
aksik [14]2 years ago
7 0

Answer:

None of the above ºC=50ºC

Step-by-step explanation:

122ºF=50ºC

Hope this helps :)

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BaLLatris [955]

f(x,y)=\dfrac{y^3}x

a. The gradient is

\nabla f(x,y)=\dfrac{\partial f}{\partial x}\,\vec\imath+\dfrac{\partial f}{\partial y}\,\vec\jmath

\boxed{\nabla f(x,y)=-\dfrac{y^3}{x^2}\,\vec\imath+\dfrac{3y^2}x\,\vec\jmath}

b. The gradient at point P(1, 2) is

\boxed{\nabla f(1,2)=-8\,\vec\imath+12\,\vec\jmath}

c. The derivative of f at P in the direction of \vec u is

D_{\vec u}f(1,2)=\nabla f(1,2)\cdot\dfrac{\vec u}{\|\vec u\|}

It looks like

\vec u=\dfrac{13}2\,\vec\imath+5\,\vec\jmath

so that

\|\vec u\|=\sqrt{\left(\dfrac{13}2\right)^2+5^2}=\dfrac{\sqrt{269}}2

Then

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7 0
3 years ago
If \: x + y + z = 0 \: then \: show \: that \: {x}^{3} + {y}^{3 } + {z}^{3} =3xy<br>​
tankabanditka [31]

Answer:

Given

x+y+z=0

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⟹x 3 +y 3 +3xy(x+y)=−z 3

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Step-by-step explanation:

Hope it is helpful.....

8 0
3 years ago
Which of the following are possible values of r?<br><img src="https://tex.z-dn.net/?f=%20%7Br%7D%5E%7B2%20%7D%20%20%3D%20%20%5Cf
marshall27 [118]

Answer:

r=\frac{\sqrt{3} }{4}    and    r=-\frac{\sqrt{3} }{4}

Step-by-step explanation:

when you solve for r in the given equation, you need to apply the square root property, which gives positive and negative answers (both should therefore be considered):

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then you need to include these two possible solutions:

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5 0
3 years ago
Please help me asapppppp​
Bas_tet [7]

Answer:

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Step-by-step explanation: Have a nice day! ✌️

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2 years ago
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xxTIMURxx [149]

Answer:

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Step-by-step explanation:

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