Can you only give brainliest on your own question?

What is the simplified form of the quantity y-squared plus 7y plus 12 over the quantity y-squared plus 8y plus 15

Burka [1]

Firstly, let's factorise each equation individually - to do this, find 2 numbers that when summed add to the value of the second term, and when multiplied give the value of the third term.

7 and 12 give us 4 and 3 (4+3=7, 4*3=12) -- 8 and 15 give us 5 and 3 (5+3=8, 5*3=15)

Now we can rewrite these equations as (y+4)(y+3) and (y+5)(y+3) respectively.

Putting this in a fraction: (y+4)(y+3)/(y+5)(y+3) -- We can clearly see that there is a y+3 on both sides of the fraction, and given there are no terms outside of the brackets being multiplied, we can directly cancel.

This gives us our final answer:
(y+4)/(y+5)

8 0

4 years ago

Help pls, I need Help :D

Oliga [24]

Answer:

5

Step-by-step explanation:

Step 1. Get two points off the graph

Points: (-70, 0) and (-60, 50)

Step 2. Use the two points to find the slope

m = slope

m = change in y/change in x

m = y2 - y1/x2 - x1

m = 50 - 0/-60 - -70

m = 50/10

m = 5/1

m = 5

The slope is 5

3 0

3 years ago

Do you think my latest video on my Chanel I am looking for true advice that can help me learn from my mistakes and grow

neonofarm [45]

Answer: ching cheng hanji, hyong hyong chino, kitchen in the dungeon, iseweyata hong kong, hoo wata hachi, asalaminontlinto asalaminonto hong kong.

Step-by-step explanation:

4 0

2 years ago

Three roots of a fifth degree polynomial function f(x) are -2, 2, and 4 + i. Which statement describes the number and nature of

Juli2301 [7.4K]

We know that imaginary roots always come in pairs, so we already know 4 solutions

-2, 2, 4 + i and a pair of 4 + i

Since imaginary roots always come in pairs we wont have more than 2 imaginary roots, since its a fifth degree root and we can only have 5 roots

So for sure, we will have 3 real roots and 2 imaginary roots

Last option, f(x) has three real roots and two imaginary roots

3 0

3 years ago

Construct the confidence interval for the population mean mu. c = 0.90, x = 16.9, s = 9.0, and n = 45. A 90% confidence inte

Georgia [21]

Answer:

The 90% confidence interval for population mean is $14.7 < \mu < 19.1$

Step-by-step explanation:

From the question we are told that

The sample mean is $\= x = 16.9$

The confidence level is $C = 0.90$

The sample size is $n = 45$

The standard deviation

Now given that the confidence level is 0.90 the level of significance is mathematically evaluated as

$\alpha = 1-0.90$

$\alpha = 0.10$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the standardized normal distribution table. The values is $Z_{\frac{\alpha }{2} } = 1.645$

The reason we are obtaining critical values for $\frac{\alpha }{2}$ instead of that of $\alpha$ is because $\alpha$ represents the area under the normal curve where the confidence level 1 - $\alpha$ (90%) did not cover which include both the left and right tail while $\frac{\alpha }{2}$ is just considering the area of one tail which is what we required calculate the margin of error