All categories

3 years ago

Find the solutions to the equation x2 - 15x - 100 = 0.

Mathematics

2 answers:

Ronch [10]3 years ago

6 0

Answer:

X= 20 or -5

Step-by-step explanation:

vfiekz [6]3 years ago

3 0

Answer:

X=-5

X=20

Step-by-step explanation:Have a brilliant day of learning! -Lily ^-^

You might be interested in

Please look at picture

olchik [2.2K]

Answer:

By sum interior angle of triangle is equal to third exterior angle hence

z = x + y

No find x and y

Sum triangle is 180 degree

5 0

3 years ago

What is the difference 7/78 - 3 1/4=

ZanzabumX [31]

<span> here
7 7/8
= [ (8*7) + 7 ] / 8
= (56 + 7) / 8
=63 / 8

similarly,
3 1/4
=[ (4*3) + 1] / 4
= (12 + 1) / 4
= 13/4

----------------------------
now put the values
7 7/8 - 3 1/4
= 63/8 - 13/4
here, take LCM of 8 & 4 which is 8.
now,
[ (1*63) - (2 * 13) ] / 8
= (63 - 26) / 8
= 37/8
= 4 5/8........................[ here, divide 37 by 8 which gives reminder as 5 and divisible value as 4 ]</span>

3 0

3 years ago

Read 2 more answers

Please help !Suppose that the height in centimeters of a candle is a linear function of them out of time in hours it has been bu

Elan Coil [88]

Answer:

17.8 cm

Step-by-step explanation:

In the 17 hours between heights of 18.6 cm and 15.2 cm, the candle lost 3.4 cm in height. That is, the height decreased at the rate of ...

(-3.4 cm)/(17 h) = -0.2 cm/h

In the 4 hours between 12 hours and 16 hours of burning time, the candle will have changed its height by (4 h)(-0.2 cm/h) = -0.8 cm.

The height at 16 hours of burning is then 18.6 cm -0.8 cm = 17.8 cm.

4 0

3 years ago

Flow meters are installed in urban sewer systems to measure the flows through the pipes. In dry weatherconditions (no rain) the

ziro4ka [17]

Answer:

a) $\frac{(8)(30.23)^2}{20.09} \leq \sigma^2 \leq \frac{(8)(30.23)^2}{1.65}$

$363.90 \leq \sigma^2 \leq 4430.80$

Now we just take square root on both sides of the interval and we got:

$19.08 \leq \sigma \leq 66.56$

b) For this case we are 98% confidence that the true deviation for the population of interest is between 19.08 and 66.56

Step-by-step explanation:

423.6, 487.3, 453.2, 402.9, 483.0, 477.7, 442.3, 418.4, 459.0

Part a

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case we need to find the sample standard deviation with the following formula:

$s=sqrt{\frac{\sum_{i=1}^8 (x_i -\bar x)^2}{n-1}}
And in order to find the sample mean we just need to use this formula:
[tex]\bar x =\frac{\sum_{i=1}^n x_i}{n}$