What is the solution of the system of inequalities y>x^2+6x+10 y<-x^2-8x-14
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The required equation is ~
Let's find the slope of given line ~
comparing it with general slope - intercept form of line (y = mx + c) we get, m = -2 (that is slope of the line)
let the slope of the required line be n
And, now since the required line Is perpendicular to the given line. the product of their slopes is -1
that is ~
slope of required line is ~ 1/2
now, let's use the point - slope form of line to find the equation of required (perpendicular) line (using point (0 , 2) ~
that is ~
here, m = slope ~
I hope it helps ~
<h3>Answer:</h3>
(1, 1), (4, -25)
<h3>Step-by-step explanation:</h3>You can evaluate the function to see.
f(-1) = -3^(-1-1)+2 = -3^(-2)+2 = -1/9 +2 ≠ 2
f(1) = -3^(1-1) +2 = -1 +2 = 1
f(0) = -3^(0-1) +2 = -1/3 +2 ≠ 0
f(4) = -3^(4 -1) +2 = -27 +2 = -25
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Or, you can graph the points and the curve.