I need help finding the area

Consider the 1-to10^19 scale on which the disk of the Milky Way Galaxy fits on a football field. On this scale, how far is it fr

bezimeni [28]

Beautiful ! What a great exercise ! I won't even check to verify
that 1:10⁻¹⁹ is an appropriate scale to map the Milky Way onto a
football field. I'll just accept it and go from there.

(4.4 light years) x (10⁻¹⁹) = (2.5848 x 10¹³ miles) x (10⁻¹⁹)

   = 2.5848 x 10⁻⁶ mile

   = 0.164 inch .

(1,391,400 kilometers) x (10⁻¹⁹) = 1.3914 x 10⁻¹⁰ meter

Research Conclusions:

If the Milky Way shrinks to fit on a football field, then

-- Alpha Centauri is 0.164 inch from us.

-- The sun's diameter is about 1.39 times that of a Hydrogen atom.

Playing with this same fun concept a little more:

-- The Earth is sailing around in its orbit, once a year,
    about 0.000015 millimeter from the sun.

-- It takes light almost 27 years to travel 1 inch !

wow !

5 0

3 years ago

Read 2 more answers

There were 29 students available for the woodwind section of the school orchestra. 11 students could play the flute, 15 could pl

Dafna11 [192]

Answer:

a. The number of students who can play all three instruments = 2 students

b. The number of students who can play only the saxophone is 0

c. The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only one of the clarinet, saxophone, or flute = 4

Step-by-step explanation:

The total number of students available = 29

The number of students that can play flute = 11 students

The number of students that can play clarinet = 15 students

The number of students that can play saxophone = 12 students

The number of students that can play flute and saxophone = 4 students

The number of students that can play flute and clarinet = 4 students

The number of students that can play clarinet and saxophone = 6 students

Let the number of students who could play flute = n(F) = 11

The number of students who could play clarinet = n(C) = 15

The number of students who could play saxophone = n(S) = 12

We have;

a. Total = n(F) + n(C) + n(S) - n(F∩C) - n(F∩S) - n(C∩S) + n(F∩C∩S) + n(non)

Therefore, we have;

29 = 11 + 15 + 12 - 4 - 4 - 6 + n(F∩C∩S) + 3

29 = 24 + n(F∩C∩S) + 3

n(F∩C∩S) = 29 - (24 + 3) = 2

The number of students who can play all = 2

b. The number of students who can play only the saxophone = n(S) - n(F∩S) - n(C∩S) - n(F∩C∩S)

The number of students who can play only the saxophone = 12 - 4 - 6 - 2 = 0

The number of students who can play only the saxophone = 0

c. The number of students who can play the saxophone and the clarinet but not the flute = n(C∩S) - n(F∩C∩S) = 6 - 2 = 4

The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only the saxophone = 0

The number of students who can play only the clarinet = n(C) - n(F∩C) - n(C∩S) - n(F∩C∩S) = 15 - 4 - 6 - 2 = 3

The number of students who can play only the clarinet = 3

The number of students who can play only the flute = n(F) - n(F∩C) - n(F∩S) - n(F∩C∩S) = 11 - 4 - 4 - 2 = 1

The number of students who can play only the flute = 1

Therefore, the number of students who can play only one of the clarinet, saxophone, or flute = 1 + 3 + 0 = 4

The number of students who can play only one of the clarinet, saxophone, or flute = 4.

6 0

3 years ago

How any is?<br> 8m + 27 = 2m - 3 <br> with procedure and testing

givi [52]

8m+27= 2m-3
take 2m and subtract it from 8m, this gives you 6m. now your equation is 6m+27=-3.
subtract 27 from -3, this will make it 6m=-30.
divide 30 by 6. this gives you your answer. m=-5, because -30 divided by 6 equals -5.
now to test it you can plug -5 into the equation in place of M. 8 times -5 equals -40, plus 27 equals -13. 2 times -5 equals -10 plus -3 equals -13.

3 0

3 years ago

Read 2 more answers

2. An empty ice cream cone has a height of 3.02 inches and a radius

ololo11 [35]

Answer:

Approximate volume of ice cream = 3.03 inches

Step-by-step explanation:

Given - An empty ice cream cone has a height of 3.02 inches and a radius

of 0.98 inches.

To find - What is the approximate volume of ice cream it will hold within the cone ?

Proof -

We know that,

Volume of the cone = $\frac{1}{3}\pi r^{2}h$

where

r is the radius of the cone

h is the height of the cone

Here,

Given that,

r = 0.98 inches

h = 3.02 inches

So,

Volume = $\frac{1}{3}\pi r^{2}h$

= $\frac{1}{3}(3.14) (0.98)^{2}(3.02)$ ( Consider the value of $\pi$ = 3.14)

= 3.0373

∴ we get

Approximate volume of ice cream = 3.03 inches

So,

The correct option is - G. 3 in 3

8 0

3 years ago

2(3r+7)−(2+r)<br> I need the answer

dimaraw [331]

Answer:

5r+12

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers