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Tresset [83]
2 years ago
5

(b)

Chemistry
1 answer:
pentagon [3]2 years ago
4 0

8%

Explanation:

In a DNA molecule the no. of Adenine bases equal to that of Thymine bases

The no. of Cytosine bases equal to that of Guamine bases.

If we take no. of Thymine bases as x and no. of Cytosine bases as y,

Adenine + Thymine + Cytosine + Guamine = 100

x + x + y+y = 100

2( x+y) = 100

x+y = 50

y=42

therefore x= 50-42 = 8%

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1. A student determines the density of water to be 0.966g/ml at a
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<u>Answer:</u>

<em>The percentage error in the measurement is 2.4% </em>

<u>Explanation:</u>

The measurement made by the student is 0.966 g/cm^3.

But the actual value of density is 0.943 g/cm^3

The formula to calculate percentage error is  

percentage error = \frac{(measured \ value-actual \ value)}{(actual  \ value)} \times 100

Hence percentage error in this case is given by

<em>Percentage error = \frac{(0.966-0.943)}{0.943} \times 100 </em>

<em>= \frac{0.023}{0.943} \times 100=2.4% </em>

A physical quantities value will be determines by various quantities. If errors are made in measuring any of these quantities there will be error in the measurement of the final physical quantity as well.

Here density of a substance is a derived quantity determined by measuring mass and volume of  that substance.<em> If errors are made in mass and volume measurements the density value will also be erroneous. </em>

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3 years ago
Which things from the image make up the pond community?
olga55 [171]
D because community is also full of abiotic factors
4 0
3 years ago
To measure the amount of calcium carbonate in a seashell, an analytical chemist crushes a sample of the shell to a fine powder a
andreyandreev [35.5K]

The given question is complete, the complete question is:

To measure the amount of calcium carbonate (CaCO) in a seashell, an analytical chemist crushes a 4.80 g sample of the shell to a fine powder and titrates it to the endpoint with 515. mL of 0.140 M hydrogen chloride (HCl) solution. The balanced chemical equation for the reaction is: 2HCI(a)Co (a) H2Co,(aq) + 2Cl (aq)

What kind of reaction is this?

If you said this was a precipitation reaction, enter the chemical formula of the precipitate.

If you said this was an acid-base reaction, enter the chemical formula of the reactant that is acting as the base.

If you said this was a redox reaction, enter the chemical symbol of the element that is oxidized

Calculate the mass percent of CaCO in the sample. Be sure your answer has the correct number of significant digits.

Answer:

It is an acid-base reaction and the mass percent of CaCo3 is 75.2%.

Explanation:

A chemical reaction in which an insoluble salt produces from two soluble salts is termed as precipitation reaction.

A reaction in which atleast exchange of one proton takes place between the two species is termed as an acid-base reaction.

A reaction in which any of the element has a change in oxidation state is termed as redox reaction.

In the mentioned reaction, there is a transfer of H⁺, no precipitation is forming, and no change in oxidation state taking place, thus, it is an acid-base reaction.

In the acid-base reaction, the base refers to the species that accepts hydrogen ion or proton. In the given case, CO₃²⁻ is accepting H+ ion to become H₂CO₃. Hence, CO₃²⁻ is the base.

In order to calculate mass percent of CaCO₃, first there is a need to find the moles of HCl reacted for a solution,

Moles = Molarity × Volume (L)

Moles = 0.140 mol/L × 515 × 10⁻³ L

Moles = 0.0721 mol

Now from the balanced equation, one mole of CaCO₃ needs two moles of HCl.

So, moles of CaCO₃ reacted will be,

= 1/2 × 0.0721 = 0.03605 mol

The mass of calcium carbonate taking part in reaction will be,

= Moles × Molar mass

= 0.03605 × 100 gram/mole

= 3.6086 gram

Mass% of CaCO₃ = Mass of CaCO₃/Mass of sample × 100

= 3.6086 grams/4.80 grams × 100

Mass % = 75.2%

3 0
3 years ago
When an excited electron in a hydrogen atom falls from ????=5 to ????=2, a photon of blue light is emitted. If an excited electr
poizon [28]

Answer:

n = 3

Explanation:

Given the formula for the transition energy of an atom with 1 electron:

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For the H transition n=5 to n=2:

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Then we solve for nf with Z=2 (Helium)

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n_{f}=\sqrt{\frac{4^{2}*2^{2}*13.6 eV }{2.856eV*4^{2}+13.6eV*2^{2}} }=3

Is near 3, actually the energy of the transitions are:

H (5⇒2) = -2.85 eV = 434 nm (Dark blue)

He (4⇒3) = -2.64 eV = 469 nm (Light blue)

I thought it was cool to see the actual colors. Included them.

4 0
3 years ago
If an atom has 7 protons, 8 neutrons and 9 electrons, what is the mass number?
Brums [2.3K]
Mass = protons + neutrons
7+8 = 15 g
3 0
3 years ago
Read 2 more answers
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