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Degger [83]
3 years ago
7

Using the first volume and temperature reading on the table as V1 and T1, solve for the unknown values in the table below. Remem

ber to use the rules of significant figures when entering your numeric response.
A:
B:

C:
D:

A 2-column table with 5 rows. Column 1 is labeled Temperature (K) with entries 295, A, 250, 325, D. Column 2 is labeled Volume (L) with entries 1.0, 1.3, B, C, 0.75.
Chemistry
2 answers:
ch4aika [34]3 years ago
6 0
A is the answer because it makes sense.
gulaghasi [49]3 years ago
6 0

Answer:

A

Explanation:

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A hot metal plate at 150°C has been placed in air at room temperature. Which event would most likely take place over the next fe
zubka84 [21]

Answer:

The air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down.

Explanation:

There will be a transfer of thermal energy (heat) from the hot metal plate to the surrounding air. This transfer of energy equates to a transfer of kinetic energy in the molecules. As the plate loses heat, the molecules in the plate will lose kinetic energy and slow down. As the surrounding air gains heat, the molecules will gain kinetic energy and speed up.

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2 years ago
Fe(s) + CuSO4(aq) ⇒ Cu(s) + FeSO4(aq)
Alexxandr [17]

Answer:

The answer to your question is CuSO₄

Explanation:

To answer your question just remember the following information

- A chemical reaction is divided into sections

 reactants and products

 reactants on the left side of the reaction

products on the right side of the reaction

- All the symbols have a meaning

 (s) means that that compound is in solid phase

 (aq) means that that compound is dissolved in solution.

Then, the answer is CuSO₄

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3 years ago
Which of the following is an example of a buoyant force acting on a piece of
hodyreva [135]

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D. The piece of bread travels with straight- line horizontal acceleration.

Explanation

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Which of the following 0.820 M solutions would have the greatest colligative effect?
eimsori [14]

Answer:

K3PO4

Explanation:

Recall that colligative properties depends on the number of particles present. The greater the number of particles present, the greater the degree of colligative properties of the solution. Let us look at each option individually;

SrCr2O7-------> Sr^2+ + Cr2O7^2- ( 2 particles)

C4H11N (not ionic in nature hence it can not dissociate into ions)

K3PO4-------> 3K^+ + PO4^3- (4 particles)

Rb2CO3-------> 2Rb^+ + CO3^2- (3 particles)

Hence K3PO4 has the greatest number of particles and will display the greatest colligative effect.

8 0
3 years ago
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