What is the percent by mass (%m/m) concentration of ammonium hydroxide (nh4oh) in a solution prepared by dissolving 8.40 g nh4oh
1 answer:
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Answer:
1. 25 moles water.
2. 41.2 grams of sodium hydroxide.
3. 0.25 grams of sugar.
4. 340.6 grams of ammonia.
5. 4.5x10²³ molecules of sulfur dioxide.
Explanation:
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In this case, since the mole-mass-particles relationships are studied by considering the Avogadro's number for the formula units and the molar mass for the mass of one mole of substance, we proceed as shown below:
1. Here, we use the Avogadro's number to obtain the moles in the given molecules of water:
2. Here, since the molar mass of NaOH is 40.00 g/mol, we obtain:
3. Here, since the molar mass of C6H12O6 is 180.15 g/mol:
4. Here, since the molar mass of ammonia is 17.03 g/mol:
5. Here, since the molar mass of SO2 is 64.06 g/mol:
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Answer:
<h3>The answer is 2 g/cm³</h3>Explanation:
The density of a substance can be found by using the formula
From the question
mass = 48 g
volume = 24 cm³
We have
We have the final answer as
<h3>2 g/cm³</h3>Hope this helps you
Answer:
Explanation:
A sigma bond is formed when a hybrid orbital sp overlaps with another hybrid orbital or with s- or p- orbital
Ethylene has a structural formula of H - C≡ C- H
At the ground state; we have :
C | ⇅ | |↑ | ↑
2s 2p
At the excited state, we have:
C | ↑ | |↑ | ↑ | ↑
the hybrid orbital
C = | ↑ | ↑ |
2sp
