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Alina [70]
2 years ago
6

True or False: This table describes a linear function. XY 1 5 2 8 3 10

Mathematics
1 answer:
VLD [36.1K]2 years ago
5 0

Answer:

False

Step-by-step explanation:

The slope is not constant

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All right guys help me out a little bit no jokes this is worth 13 points I need help with 432 / 73​
Vesna [10]

Answer:

5.91780821918

Step-by-step explanation:

432/73 is the same as 432 ÷73=5.91780821918

Hope this helps ∞<3

7 0
2 years ago
Please help me with this math problem!!!!!​
vagabundo [1.1K]

Answer:

Step-by-step explanation:

\cos ~A=0.5=cos~60 \\A=60^\circ\\B=180-A=180-60=120\\\angle~B=120^\circ

3 0
2 years ago
Find the other two vertices of a square with one vertex (0, 0) and another vertex (4, 2). Can you find another answer?
Margarita [4]

It is given that two vertices of square are (0,0) and (4,2).

Now the problem is that you haven't given that whether these two vertices are adjacent vertices or opposite vertices of the square.

1. By Supposing that these two are adjacent vertices of Square

The third vertex will be at (-4,2) which lies in third quadrant.

Suppose the coordinate of fourth vertex be (x,y).

Mid point of line joining (4,2) and (-4,2) is{ [4+(-4)]/2,(2+2)/2} is (0,2).

Mid point of line joining (x,y) and (0,0) is (x/2,y/2).

Since diagonals of square bisect each other,

∵ x/2=0

⇒x=0

and

y/2=2

⇒y=4

So, The Coordinate of  fourth vertex is (0,4).

Now coming back to second condition if these are two opposite vertex of Square.

Let the third coordinate be (a,b).

Length of diagonal=\sqrt{(4-0)^2+(2-0)^2}=\sqrt20=2\sqrt5

Now,let side of Square be A.

Then length of Diagonal of square =√2 A

⇒√2 A=2√5

⇒A =√10

As third vertex is (a,b).

Using distance formula

a² + b²=10  -------------(1)

(a-4)²+ (b-2)²=10  --------------(2)

Solving expression (1) and (2), we get

⇒a²+ b²=(a-4)² +(b-2)²

⇒2a + b =5

⇒b=5-2a

Putting the value of b in (1),we get

⇒a² +(5-2a)²=10

⇒a²+25+4a²-20a =10

⇒5a²-20a+15=0

⇒a² - 4a + 3=0

Splitting the middle term,we get

⇒(a-3)(a-1)=0

⇒a=3  ∧  a=1

we get b=5-2×1=3 and b=5-2×3=5-6=-1

So,the other vertex are (1,3) and(3,-1).





3 0
3 years ago
What is the value Of this
Lostsunrise [7]
What’s the question??
8 0
2 years ago
Anyone know the answer to this geometry problem?
hoa [83]
Let's talk about the choices
◯  ∠4 and ∠5 . . . . . . . . these are complementary angles whose sum is 90°
◯  ∠7 and ∠9 . . . . . . . . these are vertical angles, equal to each other
◯  ∠2 and ∠3 . . . . . . . . these are supplementary angles that together form a straight line. They are a linear pair.
◯  ∠1 and ∠2 . . . . . . . . these are "adjacent" angles in the quadrilateral that also includes ∠9 and ∠10.

The appropriate choice is ...
  ◉  ∠2 and ∠3
7 0
3 years ago
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