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2 years ago

14

If a friend gave a used Wii disc to someone, and they put it in their Wii, could they play it? Nintendo Switch games can only be

used on 1 switch, so is that the case?
Only answer if you know, please.

Computers and Technology

1 answer:

Nady [450]2 years ago

6 0

Any game disc or card can be used on multiple consoles

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[1] Our son has started playing organized T-ball, a beginner’s version of baseball. [2] “Organized” is what parents call it, any

k0ka [10]

I think it is 3 no? Maybe I dunno but I am confident

6 0

2 years ago

Read 2 more answers

What is the most recognized and widely used database of published nursing practice literature?

faust18 [17]

That would be the <span>Cumalitive Index to Nursing and Allied Health Literature.</span>

7 0

2 years ago

What is the formula equivalent to the function =SUM(B1:B5)? A. =B1+B5 B. =$B$1+$B$5 C. =B1+B2+B3+B4+B5 D. =$B$1+$B$2+$B$3+$B$4+$

Contact [7]

Given the options, I would choose Option C. =B1+B2+B3+B4+B5.

5 0

3 years ago

You are given a string of n characters s[1 : : : n], which you believe to be a corrupted text document in which all punctuation

alexdok [17]

Answer: provided in the explanation section

Explanation:

Given that:

Assume D(k) =║ true it is [1 : : : k] is valid sequence words or false otherwise

To determine D(n)

now the sub problem s[1 : : : k] is a valid sequence of words IFF s[1 : : : 1] is a valid sequence of words and s[ 1 + 1 : : : k] is valid word.

So, from here we have that D(k) is given by the following recorance relation:

D(k) = ║ false maximum (d[l]∧DICT(s[1 + 1 : : : k]) otherwise

Algorithm:

Valid sentence (s,k)

D [1 : : : k] ∦ array of boolean variable.

for a ← 1 to m

do ;

d(0) ← false

for b ← 0 to a - j

for b ← 0 to a - j

do;

if D[b] ∧ DICT s([b + 1 : : : a])

d (a) ← True

(b). Algorithm Output

if D[k] = = True

stack = temp stack ∦stack is used to print the strings in order

c = k

while C > 0

stack push (s [w(c)] : : : C] // w(p) is the position in s[1 : : : k] of the valid world at // position c

P = W (p) - 1

output stack

= 0 =

cheers i hope this helps !!!

8 0

3 years ago

Design and implement a class dayType that implements the day of the week in a program. The class dayType should store the day, s

Afina-wow [57]

The code is implemented based on the given operations.

Explanation:

#include <iostream>

#include <string>

using namespace std;

class dayType

{ private:

string day[7];

string presentDay;

int numofDays;

public:

void setDay(string freshDay);

void printDay() const;

int showDay(int &day);

int nextDay(int day);

int prevDay(int day) const;

int calcDay(int day, int numofDays);

dayType()

{

day[0] = "Sunday";

day[1] = "Monday";

day[2] = "Tuesday";

day[3] = "Wednesday";

day[4] = "Thursday";

day[5] = "Friday";

day[6] = "Saturday";

presentDay = day[0];

numofDays = 0;

};

~dayType();

};

#endif

#include "dayType.h"

void dayType::setDay(string freshDay)

{

presentDay = freshDay;

}

void dayType::printDay()

{

cout << "Day chosen is " << presentDay << endl;

}

int dayType::showDay(int& day)

{

return day;

}

int dayType::nextDay(int day)

{

day = day++;

if (day > 6)

day = day % 7;

switch (day)

{

case 0: cout << "The successive day is Sunday";

break;

case 1: cout << "The successive day is Monday";

break;

case 2: cout << "The successive day is Tuesday";

break;

case 3: cout << "The successive day is Wednesday";

break;

case 4: cout << "The successive day is Thursday";

break;

case 5: cout << "The successive day is Friday";

break;

case 6: cout << "The successive day is Saturday";

break;

}

cout << endl;

return day;

}

int dayType::prevDay(int day)

{

day = day--;

switch (day)

{

case -1: cout << "The before day is Saturday.";

break;

case 0: cout << "The before day is Saturday.";

break;

case 1: cout << "The before day is Saturday.";

break;

case 2: cout << "The before day is Saturday.";

break;

case 3: cout << "The before day is Saturday.";

break;

case 4: cout << "The before day is Saturday.";

break;

case 5: cout << "The before day is Saturday.";

break;

default: cout << "The before day is Saturday.";

}

cout << endl;

return day;

}

int dayType::calcDay(int addDays, int numofDays)

{

addDay = addDays + numofDays;

if (addDay > 6)

addDay = addDay % 7;

switch(addDay)

{

case 0: cout << "The processed day is Sunday.";

break;

case 1: cout << "The processedday is Monday.";

break;

case 2: cout << "The processedday is Tuesday.";

break;

case 3: cout << "The processedday is Wednesday.";

break;

case 4: cout << "The processedday is Thursday.";

break;

case 5: cout << "The processedday is Friday.";

break;

case 6: cout << "The processedday is Saturday.";

break;

default: cout << "Not valid choice.";

}

cout << endl;

return addDays;

}

4 0

2 years ago