Answer:
1st option is correct.............
➳The molar mass of copper (I) carbonate is <u>187.1 g/</u><u>mol</u>
25 grams (25g) of sugar
Explanation:
We can set this up algebraically:
10g = 2L
÷ 2 ÷ 2
5g = L
meaning that 5 g are needed to make 1 L
So, if we have 5 L, we will need (5 × 5) 25 grams to produce the same concentration.
B
since isotopeA has bigger mass number
