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Novosadov [1.4K]
2 years ago
6

An empty plastic bottle is sealed in a cool room and then moved to a very hot room. What can best be stated about the air pressu

re inside the bottle when the bottle reaches room temperature? It is lower than the pressure on the outside of the bottle. It is higher than the pressure on the outside of the bottle. It is the same as the pressure on the outside of the bottle. It exerts twice the force per unit area as the air pressure outside the bottle.
Chemistry
2 answers:
mel-nik [20]2 years ago
6 0
<span>A fast moving stream of air has a lower air pressure than a slower air stream.  As the stream of air moved over the top of the paper, the air pressure over the paper dropped. The air pressure underneath the paper stayed the same.  The greater air pressure underneath lifted the paper strip and it rose. The idea that a moving air stream has lower air pressure than air that is not moving is called “Bernoulli’s Principle”.

</span>The force of the moving air underneath the balloon was enough to hold it up.  The weight added by the paper clip prevents the balloon from going too high.  But that is only part of the story.  The balloon stays inside the moving stream of air because the pressure inside is the air stream is lower than the still air around it. As the balloon moves toward the still air outside of the air stream, the higher pressure of the still air forces the balloon back into the lower pressure of the air stream.  Bernoulli’s Principle at work again!

trasher [3.6K]2 years ago
3 0

Answer:

It is higher than the pressure on the outside of the bottle.

Explanation:

After the sealed bottle is moved from a cool room to a very hot room, the temperature of the inside gas increase. Gay-Lussac's law states that the pressure of a given mass of gas varies directly with the absolute temperature of the gas, when the volume is kept constant. Therefore, the pressure in the bottle increase.

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Match each substance with the correct designation for the equation HSO3- + CH3NH2 &lt;=&gt; SO32- + CH3NH3+ HSO3- CH3NH2 SO32- C
Zanzabum

Answer:

HSO_3^-: conjugate acid of SO_3^{2-}

CH_3NH_2 : conjugate base of CH_3NH_3^+

SO_3^{2-} : conjugate base of HSO_3^-

CH_3NH_3^+ : conjugate acid of CH_3NH_2

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

HSO_3^-+CH_3NH_2\rightleftharpoons SO_3^{2-}+CH_3NH_3^+

Here in forward reaction CH_3NH_2 is accepting a proton, thus it is considered as a base and after accepting a proton, it forms CH_3NH_3^+ which is a conjugate acid.

And HSO_3^-  is losing a proton, thus it is considered as an acid and after loosing a proton, it forms SO_3^{2-} which is a conjugate base.

Similarly in the backward reaction, CH_3NH_3^+ is loosing a proton, thus it is considered as a acid and after loosing a proton, it forms CH_3NH_2 which is a conjugate base.

And SO_3^{2-}  is accepting a proton, thus it is considered as a base and after accepting a proton, it forms HSO_3^{-} which is a conjugate acid.

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