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Artemon [7]
3 years ago
12

The hypotenuse of a right triangle is 5 meters longer than one of its legs. The other leg is 6 meters. Find the length of the ot

her leg, and round to the nearest tenth of an inch.
Mathematics
1 answer:
dedylja [7]3 years ago
8 0

Answer:

Use Pythagorean theorm.

a^2 + b^2 = c^2 (c is hypotenuse).

Let c = 5+b (because in the question it says the hypotenuse is one leg plus 5 more meters) ; we will solve for b and say it's the leg we don't know.

We will say A is the "other leg" we know, which is 6.

6^2 + b^2 = (5+b)^2

We get b = 1.1

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If the legs of an isosceles right triangle have a length of ft, the hypotenuse will have a length of?
lesya [120]
Isoceleese means then that 2 sides are equal
right triangle so the legs are equal

a^2+b^2=c^2
the legs aer a and b
in isocoleese, a=b
a^2+a^2=c^2
2a^2=c^2
if isocoleese=a then c=?
solve for c
sqrt both sides
a√2=c


if the legs are x feet, then the hyppotonuse is x√2 feet
6 0
3 years ago
the shaded area of the following shape can be found by subtracting the area of the circle from the area of the triangle?
balu736 [363]
I found the accompanying picture of this word problem.

The circle was inscribe in the triangle. The area outside of the circle but inside the triangle is the shaded area.

True. The shaded area of the following shape can be found by subtracting the area of the circle from the area of the triangle.
7 0
3 years ago
-12p^2 - 27p +27 = 0
EleoNora [17]

Answer:

that's the right answer

Step-by-step explanation:

6 0
3 years ago
Help me with this plsss 40 pointsss
lara [203]

Answer:

Step-by-step explanation:

x(3x+2)=16

3x²+2x-16=0

3x²+8x-6x-16=0

x(3x+8)-2(3x+8)=0

(3x+8)(x-2)=0

either 3x+8=0

x=-8/3(rejected as width can't be negative)

x-2=0

x=2

so width=2

length=3×2+2=6+2=8

7 0
3 years ago
You need to strengthen a 19% alcohol solution with pure alcohol solution to obtain 40% solution. How much pure alcohol should yo
Alex73 [517]
Let x be the number of mm of pure alcohol to be added:

I will add the mm to express the volume in mm
100mm.(19%) + (100%).x mL = (100 mL+x mL).(40%).
Now right again without the %
100.(0.19) + x.(1) = (100+x).(0.4)

19 + x = = 40 + 04x
x - 0.4x = 40 - 19
0.6 x = 21
x = 21/0.6  and x = 35 mL. This te quantity of pure alcohol should to be added to get a solution at 40%.



8 0
4 years ago
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