Let's solve this problem step-by-step.
STEP-BY-STEP EXPLANATION:
Let's first establish that triangle BCD is a right-angle triangle.
Therefore, we can use Pythagoras theorem to find BC and solve this problem. Pythagoras theorem is displayed below:
a^2 + b^2 = c^2
Where c = hypotenus of right-angle triangle
Where a and c = other two sides of triangle
Now we can solve the problem by substituting the values from the problem into the Pythagoras theorem as displayed below:
Let a = BC
b = DC = 24
c = DB = 26
a^2 + b^2 = c^2
a^2 + 24^2 = 26^2
a^2 = 26^2 - 24^2
a = square root of ( 26^2 - 24^2 )
a = square root of ( 676 - 576 )
a = square root of ( 100 )
a = 10
Therefore, as a = BC, BC = 10.
If we want to check our answer, we can substitute the value of ( a ) from our answer in conjunction with the values given in the problem into the Pythagoras theorem. If the left-hand side is equivalent to the right-hand side, then the answer must be correct as displayed below:
a = BC = 10
b = DC = 24
c = DB = 26
a^2 + b^2 = c^2
10^2 + 24^2 = 26^2
100 + 576 = 676
676 = 676
FINAL ANSWER:
Therefore, BC is equivalent to 10.
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The missing reason is (d) Add the fractions together on the right side of the equation
<h3>How to complete the missing reason?</h3>
From the statements, we have the following equation:
x^2 + b/a x + (b/2a)^2 = -4ac/4a^2 + b^2/4a^2
Next, we add the fractions on the right-hand side of the equation.
This gives
x^2 + b/a x + (b/2a)^2 = [-4ac + b^2]/4a^2
The above means that the last statement is gotten by adding the fractions on the right-hand side of the equation.
Hence, the missing reason is (d) Add the fractions together on the right side of the equation
Read more about quadratic equations at:
brainly.com/question/1214333
#SPJ1
Answer:
Step-by-step explanation:
a decimal
2/3 = 0.7
8/5 = 1.6
-5/2 = -2.5
7/4 = 1.8
9/2 = 4.5
-11/3 = -3.7
13/5 = 2.6
-7/4 = -1.8
Esto es solo un bosquejo del número, usando un gráfico, use 0.1 para una unidad en la recta numérica.
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-5 -4 -3.7 -3 -2.5 -2 -1.8 -1 0 0.7 1 1.6 1.8 2 2.6 3 4 4.5 5
Answer:
OD22264 is the correct answer for that
