Let
x-------> <span>Jaime budget
</span>s------> <span>fraction of Jaime budget for student tutors
</span><span>
we know that
x=(1/4)x+(3/7)x+s
3/7 is equal to-----> (3/7)*(2/2)----> 6/14
substitute
</span>x=(1/4)x+(6/14)x+s<span>
x=(7/14)x+s
s=x-(7/14)x
s=(7/14)x-------> (1/2)x------> </span>half of the budget is for <span>student tutors.
the answer is
</span>half of the budget is for student tutors
Step-by-step explanation:
E3, E6, E11, E7: no solution
E1, E12 : 1 solution
E2, E8, E10 : infinite solutions
To attempt this algebraic equation we will be multiplying 4 to (3 - x) bracket so as to form the term on L.H.S.



Combining like terms, we get,





Answer:
The quotient is (-x³ + 4x² + 4x - 8) and the remainder is 0
Step-by-step explanation:
Look to the attached file