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SIZIF [17.4K]
3 years ago
7

ANSWER FAST PLZZZZZZZZZ​

Mathematics
2 answers:
DedPeter [7]3 years ago
6 0
Here you go!!! Hope this helps!!!

trapecia [35]3 years ago
4 0

Answer:

x = 20

Step-by-step explanation:

Turn all the numbers into fractions with the same denominator.

6.75 = \frac{46}{8}

13\frac{1}{4} = \frac{53}{4} × \frac{2}{2}  = \frac{106}{8}

\frac{46}{8} + \frac{3}{8}x = \frac{106}{8}

Subtract 6.75 from both sides

\frac{3}{8}x = \frac{60}{8}

Then multiply both sides by 8

3x = 60

Then divide both sides by 3 to get x

\frac{3x}{3} = \frac{60}{3}

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The total amount spent by some number of people on clothing and footwear In the years 2000-2009 can be modeled by the quadratic
FinnZ [79.3K]

For this problem, we are given a quadratic equation that models the total amount spent on clothing and footwear in the years 2000-2009. We need to use the model to determine the maximum amount spent during the period.

The equation is shown below:

f(x)=-4.462x^2+71.54x+97.44

Since the leading term is negative, the vertex of this function will represent an absolute maximum value. Therefore we can determine the vertex to answer the problem, the vertex's coordinates are given below:

\begin{gathered} x_{max}=\frac{-b}{2a}\\ \\ y_{max}=f(x_{max}) \end{gathered}

Then we have:

\begin{gathered} x_{max}=\frac{-71.54}{2\cdot(-4.462)}=8.017\\ \\ y_{max}=-4.462\cdot(8.017)^2+71.54\cdot(8.017)+97.44=384.2 \end{gathered}

In the year 2008, 384 billion was spent on clothing and footwear.

4 0
1 year ago
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