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notka56 [123]
3 years ago
14

A line with a slope of -6 passes through the point (-8, -3). What is its equation in point-

Mathematics
1 answer:
MAVERICK [17]3 years ago
8 0

Answer:

y+3=-6(x+8)

Step-by-step explanation:

Because we already know a point and the slope, we can put our equation in the form y-y1=m(x-x1);

y+3=-6(x+8)

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What is the quotient of 3.12 x 108 and 2.6 x 105 expressed in scientific notation?​
Gnoma [55]

Answer:

1.2 * 10^3

Step-by-step explanation:

3.12 * 10^8

=========

2.6 * 10^5

Start by doing 3.12 / 1.6 = 1.2 and that is the correct number of sig digs.

Now get the power on the 10. When dividing, the powers subtract.

10^(8 - 5)

10^ 3

The answer is 1.2 * 10^3

7 0
3 years ago
What is the y-intercept of this graph?<br> A. 0<br> B. 2<br> C. 4<br> D. 8
WITCHER [35]

Answer: 0

Step-by-step explanation:

The line runs through the coordinate (0,0), rather than starting at (0,2), (0,4), or (0,8).

Always remember that you read coordinates as (x,y) which..

X is how many spaces right or left

Y is how many spaces up or down.

8 0
3 years ago
Read 2 more answers
What is the answer to <br> R/10 + 4 = 5
lesantik [10]

Answer:

R = 10.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Divided the following rational expressions<br> t^3-t^2-2t/t-5 divided by t^2-t-2
butalik [34]

t³-t²-2t/t -5 )/(t²-t-2)

(t^4-t^3-7t)/t^3-t^2-2t)

(t³-t²-7)/(t²-t-2)


I hope that's help !

7 0
4 years ago
JKLM is a rhombus. KM is 6 and JL is 8. Find the perimeter of the rhombus. image of rhombus JKLM with diagonals JL and KM inters
VLD [36.1K]
If a quadrilateral is a rhombus then:

i) all its sides have equal length,

and

ii) the 2 diagonals are perpendicular and bisect each other.


The 2 diagonals of rhombus JKLM intersect at N.

Then m(MNJ)=90°,  |JN|=4 and |NM|=3 units

thus, by the Pythagorean theorem, 

|MJ|= \sqrt{ 3^{2} + 4^{2} }= \sqrt{9+16}= \sqrt{25}=5

The perimeter of the rhombus is 4*5 units=20 units.


Answer: 20 units 

4 0
3 years ago
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