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3 years ago

To get to the next term in this sequence, multiply the last term by 2.5. What is the value of the next term?

Mathematics

1 answer:

nirvana33 [79]3 years ago

6 0

<h3><u>Question:</u></h3>

"To get the next term in the sequence,multiply the last term by 2.5 . What is the value of the next term?

1 , 2.5 , 6.25, 15.625, ..."

<h3><u>Answer:</u></h3>

The value of the next term is 39.0625

<h3><u>Solution:</u></h3>

Given that the series is 1 , 2.5 , 6.25, 15.625

When we divide 2nd term by first we get 2.5 , similarly for other successive number when we divide them with their preceding number we get a value of 2.5

So, all the successive numbers are 2.5 times of their previous number

$1 \times 2.5 = 2.5\\\\2.5 \times 2.5 = 6.25\\\\6.25 \times 2.5 = 15.625\\\\15.625 \times 2.5 = 39.0625$

So the value of next term is 39.0625

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Answer:

Jaime's. Interval not centered around the point estimate.

Step-by-step explanation:

When constructing a confidence interval based on a point estimate, the obtained point estimate must be the central value of the interval.

For Jaime's interval

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For Mariya's interval

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For a point estimate of 0.12, only Mariya's interval is adequate since Jaime's is not centered around the point estimate.

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2 years ago

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2 years ago

What is the limit of f (×) as x approaches - infinty

tatyana61 [14]

If the degree of numerator and denominator are equal, then limit will be leading coefficient of numerator divided by the leading coefficient of denominator.

So then the limit would be 3/1 = 3.

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2 years ago

Lakiesha is an employee who drives a 2019 Buick Verano as a company car. The fair-market value of the car is $28,545. She has be

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Answer:

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The lease value may bed defined as an open market capital valuation of the parts of the subject or the subject that are to be leased in regards of the terms of the lease.

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2 years ago

A charter airline finds that on its Saturday flights from Philadelphia to London, all 120 seats will be sold if the ticket price

Nataliya [291]

Answer:

a) $P=3(120-s)+200$

b) $215 \leq P \leq 290$

Step-by-step explanation:

For this case we can use a linear model to solve the problem.

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So for this case we just need to replace the limits into the linear equation and see what we got:

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So the corresponding range of ticket prices is:

$215 \leq P \leq 290$

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