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Marrrta [24]
2 years ago
13

Yall I just realized I skipped 4 and 5- but here's question 4

Mathematics
1 answer:
natali 33 [55]2 years ago
8 0
The sum of five and the quotient of two and four
because u do division first
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17=14 3/4+ 1/6+ missing number
Lostsunrise [7]
1. 1/3 for 14 3/4+ 1/6= 15 6/12 now 17 -15 6/12 =1 6/12 which is the same as 1 1/3
3 0
3 years ago
5) Mrs. Bell went bowling again. Her bowling scores were 100, 172, 85, and 92. She wants
Alex73 [517]

Answer: She needs to bowl 120 or more on her next game.

Step-by-step explanation:

8 0
3 years ago
HELP!!!<br> ANSWER FAST. PLEASEEE
kari74 [83]

Answer:

The answer would be $2.

Have a nice day.

4 0
3 years ago
Read 2 more answers
Help
marissa [1.9K]
The answer is 188 altogether 
5 0
3 years ago
Read 2 more answers
the value of c guaranteed to exist by the Mean Value Theorem for V(x) = x² in the interval [0, 3] is...? a) 1 b) 2 c) 3/2 d) 1/2
lilavasa [31]

Answer:  c) \dfrac{3}{2} .

Step-by-step explanation:

Mean value theorem : If f(x) is defined and continuous on the interval [a,b] and differentiable on (a,b), then there is at least one number c in the interval (a,b) (that is a < c < b) such that

\begin{displaymath}f'(c) = \frac{f(b) - f(a)}{b-a} \cdot\end{displaymath}

Given function : f(x) = x^2

Interval : [0,3]

Then, by the mean value theorem, there is at least one number c in the interval (0,3) such that

f'(c)=\dfrac{f(3)-f(0)}{3-0}\\\\=\dfrac{3^2-0^2}{3}=\dfrac{9}{3}\\\\=3

\Rightarrow\ f'(c)=3\ \ \ ...(i)

Since f'(x)=2x

then, at x=c, f'(c)=2c\ \ \ ...(ii)

From (i) and (ii), we have

2c=3\\\\\Rightarrow\ c=\dfrac{3}{2}

Hence, the correct option is c) \dfrac{3}{2} .

4 0
3 years ago
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