2 years ago

Yall I just realized I skipped 4 and 5- but here's question 4

Mathematics

1 answer:

natali 33 [55]2 years ago

8 0

The sum of five and the quotient of two and four
because u do division first

You might be interested in

Graph the equation below by plotting the y-intercept and a second point on the line.<br> Y=3x-3

Zinaida [17]

y-intercept is -3 so it must pass the vertical line -3.

Now start from point (0,-3) and rise up by 3, then go right by 1 since the slope is 3/1 or 3.

It should look like this:

8 0

2 years ago

Pls help me out plss

Wewaii [24]

Answer:

1.5 white and 2 blue is an equivalent ratio

Step-by-step explanation:

8 0

3 years ago

Put the differential equation 9ty+ety′=yt2+81 into the form y′+p(t)y=g(t) and find p(t) and g(t). p(t)= help (formulas) g(t)= he

alexgriva [62]

Answer:

$p(t) = \frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) }$

g(t) = 0

And

The differential equation $9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$ is linear and homogeneous

Step-by-step explanation:

Given that,

The differential equation is -

$9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$

$e^{t}y' + (9t - \frac{1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t(t^{2} + 81 ) - 1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t^{3} + 729t - 1}{t^{2} + 81 } )y = 0\\y' + [\frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) } ]y = 0$

By comparing with y′+p(t)y=g(t), we get

$p(t) = \frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) }$

g(t) = 0

And

The differential equation $9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$ is linear and homogeneous.

6 0

2 years ago

18.25=4(1.5-3.75x)-.25(4x-5) wat is x?

sdas [7]

The answer is x= - 11/ 16
You can check this by plugging in x for -11/16

5 0

2 years ago

Im having trouble finding facts that are in scientific notation. a good example is: a microbe is 1.23*10^-3 small. (this is not

Afina-wow [57]

Mass of electron:9.109 times 10^-31 kg
mass of proton: 1.673 times 10-27
speed of light=3.0 times 10^8
avogadro's number 6.02 times 10^32
planck's constant: 6.63 times 10^-34
just google chem constants sheet

4 0

3 years ago

Read 2 more answers