Answer:
y = 5x2 + 10x - 15
We want this in format y = a(x-h)2 + k
where the vertex will be at (h,k)
y = 5(x2+2x) - 15
Complete the square on x2+2x
y = 5(x2+2x+1) - 15 - 5
We subtract 5 at the end because we are actually adding 5(1) = 5
so we need to remove it also to keep the total equal
y = 5(x+1)2 - 20
The vertex is at (-1,-20)
Ax + 32 = 6
- 32 = -32
---------------------
ax = -26
---- -----
a a
1x = -26
-----
a
x = -26
-----
a
Answer:
27.22
Step-by-step explanation:
I just done it. it wasnt that hard
We know that
cos A=adjacent side angle A/hypotenuse
adjacent side angle A=24 units
hypotenuse=26 units
cos A=24/26-----> 12/13
cos B=adjacent side angle B/hypotenuse
adjacent side angle B=10 units
hypotenuse=26 units
cos B=10/26------> 5/13
the answers are
cos A=12/13
cos B=5/13
cot A=adjacent side angle A/opposite side angle A
adjacent side angle A=24 units
opposite side angle A=10 units
cot A=24/10------> cot A=12/5
cot B=adjacent side angle B/opposite side angle B
adjacent side angle B=10 units
opposite side angle B=24 units
cot B=10/24------> cot B=5/12
