The answer is A.) 5x+8y≤120
To get this answer the first thing I did was notice what it says the x and y variables stand for. The "x variable represents the number of breadsticks purchased" and "the y variable represents the number of pizza pies purchased". It also says that each breadstick is $5 and each pizza pie is $8. Accordingly, we need to match our variables with what we're buying. So, the y be with 8 and the x be with 5.
So, our expression will have a 5x and an 8y in it.
Now if we notice, it says he can spend no more than $120, so that means he can spend $120 or less. The less than or equal to sign is ≤.
Now we can find our answer. The only answer with 5x and 8y with a ≤120 is answer choice A
Hope this helped!! :))
The error is in the second step they subtracted 3 from both sides but it was a 3x, which you can not do.
Correction.
9x+18+3x=1
12x+18=1
12x=-17
x=-17/12
Answer:
15.75 cups
Step-by-step explanation:
If she uses 1.75 cups each batch to find how much she uses for 9 batches you just multiply 1.75 by 9 which gives you 15.75 cups
Answer:
answers below
Step-by-step explanation:
1. no
2. yes
3. no
4. yes
5. no
6. yes
7. no
8. no
9. no
10. no
11. no
12. yes
Answer:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
Step-by-step explanation:
For this case first we need to create the sample of size 20 for the following distribution:
And we can use the following code: rnorm(20,50,6) and we got this output:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
