Answer:
- x = 30°
- RS = 30°, SR = TU = 120°, UR = 90°
- ∠P = 45°
- ∠UTS = 60°
Step-by-step explanation:
(a) If RS = x, then the sum of arcs around the circle is ...
x + 4x +4x +3x = 360°
12x = 360°
x = 30°
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(b) Based on the given ratios, the arc measures are computed from x. For example, ST = TU = 4x = 4(30°) = 120°
- RS = 30°
- ST = 120°
- TU = 120°
- UR = 90°
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(c) Angle P is half the difference of arcs TU and RS:
∠P = (TU -RS)/2 = (120° -30°)/2
∠P = 45°
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(d) Inscribed angle UTS is half the measure of the arc it intercepts. Arc RU has the measure (30° +90°) = 120°, so the measure of UTS is ...
∠UTS = 120°/2 = 60°
Answer:
The number line is missing, but as we are know that the number marked in the number line is -6/4, i will guess that the ticks are spearated by fourts (the distance between each tick is 1/4).
Now, for the number at the right of -6/4, we should add the distance for one tick, this means that the number at the right is:
-6/4 + 1/4 = -5/4.
Now i will give some other examples:
Now, if the distance between ticks is 2/4, then the number at the right will be:
-6/4 + 2/4 = -4/4 = -1
Now, if the distance between ticks is 3/4, the the number at the right will be:
-6/4 + 3/4 = -3/4.
Answer: 18
Step-by-step explanation:
The circumference formula is C= 2
r
r being the radius, so you can just plug in.
C= 2
(9) = 18
Answer:
D = L/k
Step-by-step explanation:
Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is
dA/dt = in flow - out flow
Since litter falls at a constant rate of L grams per square meter per year, in flow = L
Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow
So,
dA/dt = in flow - out flow
dA/dt = L - Ak
Separating the variables, we have
dA/(L - Ak) = dt
Integrating, we have
∫-kdA/-k(L - Ak) = ∫dt
1/k∫-kdA/(L - Ak) = ∫dt
1/k㏑(L - Ak) = t + C
㏑(L - Ak) = kt + kC
㏑(L - Ak) = kt + C' (C' = kC)
taking exponents of both sides, we have

When t = 0, A(0) = 0 (since the forest floor is initially clear)


So, D = R - A =

when t = 0(at initial time), the initial value of D =

Answer: b
Step-by-step explanation:
1. For any type of data a line graph and bar work but sense u are comparing a double line graph is best