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Pachacha [2.7K]
3 years ago
8

The members of a book club spend the same amount of money for refreshments at each meeting. At one meeting they bought 6 bagels

and spent $9.00 on beverages. At the next meeting they bought 8 bagels and spent $8.20 on beverages. What was the cost of each bagel?
Mathematics
1 answer:
Tom [10]3 years ago
8 0

The members of a book club spend $0.4 for each Bagel as refreshment.

Let x represent the cost of each bagel.

At a meeting, they bought 6 bagels and spent $9.00 on beverages, hence:

Cost = 6x + 9

At another meeting, they bought 8 bagels and spent $8.20 on beverages, hence:

Cost = 8x + 8.20

Since the same money is spent on each meeting, hence:

6x + 9 = 8x + 8.2

2x = 0.8

x = $0.4

Therefore the cost of each bagel is $0.4

Find out more at: brainly.com/question/13911928

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fiasKO [112]

Answer:

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Step-by-step explanation:

(a) If RS = x, then the sum of arcs around the circle is ...

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  12x = 360°

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(b) Based on the given ratios, the arc measures are computed from x. For example, ST = TU = 4x = 4(30°) = 120°

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(c) Angle P is half the difference of arcs TU and RS:

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(d) Inscribed angle UTS is half the measure of the arc it intercepts. Arc RU has the measure (30° +90°) = 120°, so the measure of UTS is ...

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4 0
3 years ago
Which rational number is one tick mark to the right of Negative 6 Over 4 on the number line below?
murzikaleks [220]

Answer:

The number line is missing, but as we are know that the number marked in the number line is -6/4, i will guess that the ticks are spearated by fourts (the distance between each tick is 1/4).

Now, for the number at the right of -6/4, we should add the distance for one tick, this means that the number at the right is:

-6/4 + 1/4 = -5/4.

Now i will give some other examples:

Now, if the distance between ticks is 2/4, then the number at the right will be:

-6/4 + 2/4 = -4/4 = -1

Now, if the distance between ticks is 3/4, the the number at the right will be:

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Answer:

D = L/k

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Since litter falls at a constant rate of L  grams per square meter per year, in flow = L

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dA/(L - Ak) = dt

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㏑(L - Ak) = kt + C'      (C' = kC)

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