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Pachacha [2.7K]
2 years ago
8

The members of a book club spend the same amount of money for refreshments at each meeting. At one meeting they bought 6 bagels

and spent $9.00 on beverages. At the next meeting they bought 8 bagels and spent $8.20 on beverages. What was the cost of each bagel?
Mathematics
1 answer:
Tom [10]2 years ago
8 0

The members of a book club spend $0.4 for each Bagel as refreshment.

Let x represent the cost of each bagel.

At a meeting, they bought 6 bagels and spent $9.00 on beverages, hence:

Cost = 6x + 9

At another meeting, they bought 8 bagels and spent $8.20 on beverages, hence:

Cost = 8x + 8.20

Since the same money is spent on each meeting, hence:

6x + 9 = 8x + 8.2

2x = 0.8

x = $0.4

Therefore the cost of each bagel is $0.4

Find out more at: brainly.com/question/13911928

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The properties of the mathematical sequence allow us to find that the recurrence term is 1 and the operation for each sequence is

   a) Subtraction

   b) Addition

   c) AdditionSum

   d) in this case we have two possibilities

       * If we move to the right the addition

       * If we move to the left the subtraction

The sequence is a set of elements arranged one after another related by some mathematical relationship. The elements of the sequence are called terms.

The sequences shown can be defined by recurrence relations.

Let's analyze each sequence shown, the ellipsis indicates where the sequence advances.

a) ... -7, -6, -5, -4, -3

We can observe that each term has a difference of one unit; if we subtract 1 from the term to the right, we obtain the following term

        -3 -1 = -4

        -4 -1 = -5

        -7 -1 = -8

Therefore the mathematical operation is the subtraction.

b) 0. \sqrt{1}. \sqrt{4}, \sqrt{9}, \sqrt{16}, \sqrt{25}  ...

In this case we can see more clearly the sequence when writing in this way

      0, \sqrt{1^2}. \sqrt{2^2}, \sqrt{3^2 } . \sqrt{4^2} , \sqrt{5^2}

each term is found by adding 1 to the current term,

      \sqrt{(0+1)^2} = \sqrt{1^2} \\\sqrt{(1+1)^2} = \sqrt{2^2}\\\sqrt{(2+1)^2} = \sqrt{3^2}\\\sqrt{(5+1)^2} = \sqrt{6^2}

Therefore the mathematical operation is the addition

c)   ... \frac{-10}{2}. \frac{-8}{2}, \frac{-6}{2}, \frac{-4}{2}. \frac{-2}{2}. ...

      The recurrence term is unity, with the fact that the sequence extends to the right and to the left the operation is

  • To move to the right add 1

           -\frac{-10}{2} + 1 = \frac{-10}{2}  -   \frac{2}{2}  = \frac{-8}{2}\\\frac{-8}{2} + \frac{2}{2} = \frac{-6}{2}

  • To move left subtract 1

         \frac{-2}{2} - 1 = \frac{-4}{2}\\\frac{-4}{2} - \frac{2}{2} = \frac{-6}{2}

         

Using the properties the mathematical sequence we find that the recurrence term is 1 and the operation for each sequence is

   a) Subtraction

   b) Sum

   c) Sum

   d) This case we have two possibilities

  •  If we move to the right the sum
  •  If we move to the left we subtract

Learn more here: brainly.com/question/4626313

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3 years ago
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Because you are distributing the 3 to 2/5x and 7/5y
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Evaluate the expression 7x to the power of 2y, when x = 5 and y = 3.
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The answer is 210 hope this helps
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