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zvonat [6]
3 years ago
9

Find the area of the grey pathway

Mathematics
2 answers:
creativ13 [48]3 years ago
8 0

52 square metres

Step-by-step explanation:

we can divide the pathway in to 2 parts to find the area

1st part

length = 12m

breadth = 2m

area = 12 \times 2 =  {24}^{2}m

2nd part

length = 16-2 = 14

breadth = 2

area =

area = 14 \times 2 =  {28}^{2} m

atlast add both areas

52 square metres

morpeh [17]3 years ago
6 0

Answer:

<h2><u><em>52m²</em></u></h2>

Step-by-step explanation:

<em>find the area of ​​the horizontal rectangle, add it to the vertical rectangle and remove the common part</em>

2 * 16 + 2 * 12  - 2 * 2 =

52m²

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babunello [35]

Answer:

-1

Step-by-step explanation:

Plug in given values

-4x + 5y + 6z

-4(-2) + 5(3) + 6(-4)

8 + 15 -24

23-24

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3 years ago
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Wayne bought an engagement ring for Tracy.
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It would be: 420 + (420 * 17.5%)
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In triangle ABC above, AD is perpendicular to CB. If the lengths of AD and CB were both increased by 50%, how would the area of
astra-53 [7]

Answer:

The answer is below

Step-by-step explanation:

A triangle is a polygon with three sides and three angles. There are different types of triangles such as scalene triangle, equilateral triangle, isosceles triangle.

The area of a triangle is given as:

A = (1/2) * b * h

where b = base of triangle, h = height of triangle , A = area

Let BC = base = x, and AD = height = y, hence:

A = (1/2) * x * y = 0.5xy

If the lengths of AD and CB were both increased by 50%, hence:

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The new area= (1/2) * 1.5y * 1.5x = 1.125xy

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3 0
3 years ago
I need help answering this question, Asap
Natasha2012 [34]

Answer:

(-65)/17

Step-by-step explanation:

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3/(x - 2) - sqrt(x - 3) = 3/(19 - 2) - sqrt(19 - 3)

19 - 3 = 16:

3/(19 - 2) - sqrt(16)

19 - 2 = 17:

3/17 - sqrt(16)

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3/17 - 2^2

2^2 = 4:

3/17 - 4

Put 3/17 - 4 over the common denominator 17. 3/17 - 4 = 3/17 + (17 (-4))/17:

3/17 - (4×17)/17

17 (-4) = -68:

3/17 + (-68)/17

3/17 - 68/17 = (3 - 68)/17:

(3 - 68)/17

3 - 68 = -65:

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