In triangle ABC above, AD is perpendicular to CB. If the lengths of AD and CB were both increased by 50%, how would the area of
1 answer:
Answer:
The answer is below
Step-by-step explanation:
A triangle is a polygon with three sides and three angles. There are different types of triangles such as scalene triangle, equilateral triangle, isosceles triangle.
The area of a triangle is given as:
A = (1/2) * b * h
where b = base of triangle, h = height of triangle , A = area
Let BC = base = x, and AD = height = y, hence:
A = (1/2) * x * y = 0.5xy
If the lengths of AD and CB were both increased by 50%, hence:
new AD = y + 0.5y = 1.5y, new CB = x + 0.5x = 1.5x
The new area= (1/2) * 1.5y * 1.5x = 1.125xy
Increased area / area = 1.125xy / 0.5xy = 2.25
If the lengths are increased by 50%, the area would also increase and the new area would be 2.25 times
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Answer:
Option A.
Step-by-step explanation:
From the first dot plot the given data set for week 1 is
62, 68, 68, 68, 69, 70, 70, 72, 72, 72, 75, 75, 76, 78, 78, 80, 80, 80, 89, 89
Divide the data in 4 equal parts.
(62, 68, 68, 68, 69), (70, 70, 72, 72, 72), (75, 75, 76, 78, 78), (80, 80, 80, 89, 89)
From the second dot plot the given data set for week 2 is
62, 68, 68, 68, 69, 70, 70, 72, 72, 72, 75, 75, 76, 78, 78, 80, 80, 80, 85, 86, 86, 86, 88, 88, 88, 88, 89, 89, 89, 89
Divide the data in 4 equal parts.
(62, 68, 68, 68, 69, 70, 70), 72, (72, 72, 75, 75, 76, 78, 78), (80, 80, 80, 85, 86, 86, 86), 88, (88, 88, 88, 89, 89, 89, 89)
The range for Week 1 is equal to the range for Week 2.
The median for Week 2 is more than the median for Week 1.
The mean for Week 2 is more than the mean for Week 1.
Therefore, the correct option is A.