B.
15, 19, 20, 25, 25, 28, 29, 30, 35, 37, 38, 43
43-15=28
answer=28 is the range of the data set.
showed my work and everything, hope this helps!!
Answer:
160,000 tins
Step-by-step explanation:
To find the number of tins, divide the fill rate by the volume per tin.
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(2·(1000 L)/min)×(60 min)/(1 h)/(0.75 L/tin) = 160,000 tin/h
160,000 tins of paint can be filled in 1 hour.
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<em>Additional comment</em>
That's one tin every 22.5 milliseconds. It would be a feat of engineering to move that volume without splashing.
There are 60 minutes per hour. There are 1000 liters per cubic meter.
Hope you understand it and see what I did.
Answer:
The class width is 20
Step-by-step explanation:
In a frequency or a relative frequency distribution the class width is calculated as the difference between the lower or upper class limits of consecutive classes. A point to note is that all the categories or classes usually have the same class width.
We use the first two classes to calculate the class width by using their respective upper limits;
Class width = 89 - 69
Class width = 20