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lozanna [386]
3 years ago
11

A recent survey determined the IQ score of a random selection of residents of Alaska. The accompanying relative frequency distri

bution table summarized the results.
Identify the class width for the given relative frequency distribution.

Mathematics
1 answer:
ycow [4]3 years ago
4 0

Answer:

The class width is 20

Step-by-step explanation:

In a frequency or a relative frequency distribution the class width is calculated as the difference between the lower or upper class limits of consecutive classes. A point to note is that all the categories or classes usually have the same class width.

We use the first two classes to calculate the class width by using their respective upper limits;

Class width = 89 - 69

Class width = 20

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The Ratio of boys to girls in Martin Middle school is 3/2. what is the percent of the entire school is boys?
Llana [10]

3+2=5

5x=100%

x=20 (divide)

20*3=60

60% are boys, 40% are girls

6 0
3 years ago
Consider the function. What is the y-intercept of f–1(x)? –16 –12
Mekhanik [1.2K]
<h2>Explanation:</h2><h2></h2>

Hello! Remember you have to write clear questions in order to get good and exact answers. Here, I'll assume the function as:

f(x)=x^2+2x-16

The y-intercept of a function is the point at which the graph of the function touches the y-axis. This occurs when we set x=0. In other words, we define the y-intercept (let's call it b as:

b=f(0)

Setting x=0 in our function we have:

b=f(0)=(0)^2+2(0)-16 \\ \\ \boxed{b=f(0)=-16}

So <em>in this context the y-intercept is -16</em>

7 0
2 years ago
Brenda records 76 songs on 4 albums write as a rate
Ad libitum [116K]
19 songs per album
djdjdjd djdjdjd jdjdjdjdkdkdkdkdkdkdjxndmdmdjddjjdjddjdjdjdjdjfj or 19/1
6 0
2 years ago
In the figure below, AB=AE, AC=AD and AP is perpendicular to BE. Prove that BC=DE.
NISA [10]

Step-by-step explanation:

1) In the figure, as AB is equal to AE, ABE is an equilateral triangle.

As AP is perpendicular to BE

=> AP is the height of the triangle ABE.

In an equilateral triangle, the median and the height is the same, so that AP is also the median of the triangle.

=> P is the midpoint of BE

=> PE = PB

2) In the figure, as AC = AD, so that ACD is an equilateral triangle.

As AP is perpendicular to BE,  so that it is perpendicular to CD as well

=> AP is the height of the triangle ACD

In an equilateral triangle, the median and the height is the same, so that AP is also the median of the triangle ACD.

=> P is the midpoint of CD

=> PC = PD

We have:

+) PB = PE

+) PC = PD

=> PB - PC = PE - PD => BC = DE

5 0
3 years ago
(image) The figure below is an isosceles triangle surmounted by a semi-circle. Find the area of the entire region.
S_A_V [24]

Answer:

12.53

Step-by-step explanation:

∠BCA = (180°-40°)/2 = 70°

Laws of Sines: CA/sin 40° = AB/sin 70° = 5/sin 70°

CA = 5/sin 70° * sin 40° = 3.40

area of semicircle CA = (3.1416 * 1.70²) / 2 = 4.54

By Heron's Formula, area of triangle ABC:

1/4 √(a+b+c) (a+b-c) (b+c-a) (c+a-b) = 1/4 * √13.4*3.4*3.4*6.6

                                                          = 7.99

Entire region area = 4.54 + 7.99 = 12.53

5 0
1 year ago
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