i can only help you with the volume of #5.
So the volume of a cylinder is = πr²h.
First , put the numbers in the equation.
π(6)² (14)
Next you solve.
π(6)²(14) = 36 (14) π = 504π
V= 504π
Answer:
Ix = Iy =
Radius of gyration x = y = 
Step-by-step explanation:
Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.
Mass of disk = ρπR2
Moment of inertia about its perpendicular axis is
. Moment of inertia of quarter disk about its perpendicular is
.
Now using perpendicular axis theorem, Ix = Iy =
=
.
For Radius of gyration K, equate MK2 = MR2/16, K= R/4.
Answer:
v = 18
Explain:
Equation; 4v = 72
Begin by dividing both sides
by 4 and isolating the v
v = 18
hopefully this helps you with your problem!
(a brainliest would be appreciated)