Helpppp me pleaseeee :}
2 answers:
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The graph looks like this, on the enclosed pic:
One feature is that it's periodic and torn (has cut-off points), meaning the domain is the same as in case of tan(x): x€R and x =/= π/2+πn.
The range equals the range of arcsin(x): -π/2<=y<=π/2 OR y€[-π/2;π/2]
Hope could understand and if it helped! :)
One feature is that it's periodic and torn (has cut-off points), meaning the domain is the same as in case of tan(x): x€R and x =/= π/2+πn.
The range equals the range of arcsin(x): -π/2<=y<=π/2 OR y€[-π/2;π/2]
Hope could understand and if it helped! :)
Answer:
219m
Step-by-step explanation:
Since the man observes the car with angle 15 before observing in 33 degrees.
For the first observation
The angle observation gives an angle if 33 degrees with the horizontal.
It gives a triangle which I'll attach to the que,
from the first triangle
Tan 33 = 100/y
Y= 100/ tan 33
Y = 153.99m.
This is the distance from the building to the distance where it was secondly observed( 33).
To find x
tan 15 = 100/(153.99+x)
153.99 + x = 100/ tan 15
153.99 + x = 373.21
The distance between the two observed angles
X= 219m.
