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trasher [3.6K]
3 years ago
5

HELP PLS! At a raffle, 100 tickets are sold for 1 prize of $100 and 3 consolation prizes of $20. What prizes should the tickets

be sold for if the goal is to make the raffle a fair game?
Mathematics
1 answer:
Finger [1]3 years ago
7 0

Step-by-step explanation:

I assume "fair game" means that there is no profit and the expenses are equal to the income or sales.

we have clear expenses :

1× $100

3× $20

that is in total : $160

now we need to make sure that we generate exactly $160 by selling the tickets.

we have 100 tickets that should lead to $160.

how much should 1 ticket cost ?

well, 160/100 = $1.60

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Evaluate 5y+x2÷2 when x=4 and y=−3. When x=4 and y=−3, 5y+x2÷2=
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6 0
4 years ago
Each contestant in the Hunger Games must be trained to compete. Suppose that the time it takes to train a contestant has mean 5
LiRa [457]

Answer:

11.51% probability that it will take less than 450 days to train all the contestants.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For the sum of n variables, the mean is \mu*n and the standard deviation is s = \sigma\sqrt{n}

In this question:

n = 100, \mu = 100*5 = 500, s = 4\sqrt{100} = 40

Approximate the probability that it will take less than 450 days to train all the contestants.

This is the pvalue of Z when X = 450.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{450 - 500}{40}

Z = -1.2

Z = -1.2 has a pvalue of 0.1151

11.51% probability that it will take less than 450 days to train all the contestants.

8 0
4 years ago
What is the value of the expression when n=3 6(n^2+2)/n<br><br> 16<br> 22<br> 30<br> 66
Kipish [7]
The correct answer is:  [B]:  " 22 " . 
_________________________________________________________
Explanation:
_________________________________________________________
Given:
_________________________________________________________

\frac{6(n^2 + 2)}{3} ;

Solve when:  "n = 3" ; 

Rewrite the expression; substituting "3" for all values of "n" ; as follows:

  →  \frac{6(3^2+2)}{3} ; 

The "6" cancels out to "2" ; & the "3" cancels out to "1" ; 

→  {since:  " {6 ÷ 3 = 2}" ; and since:  " {2 ÷ 2 = 1}" .
_________________________________________________________
→  Since the "denominator" is "1" ; and any value, divided by "1";  results in that original value;  we can eliminate the denominator.

→  Now, we can rewrite the expression as:
_________________________________________________________
     →  "  2(3² + 2)"  ; 

            =  2(9 + 2) ; 

            =  2(11) ;

            =  " 22 " . 
_________________________________________________________
  →  The answer is:  " 22 " ;   which is:  Answer choice:  [B]:  " 22 " . 
_________________________________________________________
4 0
3 years ago
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