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Montano1993 [528]
3 years ago
15

Here are the first five terms of an arithmetic sequence.

Mathematics
1 answer:
Assoli18 [71]3 years ago
8 0

Answer:

The nth term of an AP will be 27 -7n.

Step-by-step explanation:

First five terms of the Arthemetic Sequence is given to us , which is 26 , 19 , 12 , 5

Hence here Common Difference can be found by subtracting two consecutive terms . Here which is 19 - 26 = (-7) .

Here first term is 26 .

And the nth term of an AP is given by ,

★ T_n = a + ( n - 1) d

<u>Subst</u><u>ituting</u><u> respective</u><u> values</u><u> </u><u>,</u>

⇒ T_n = a + ( n - 1 )d

⇒ T_n = 26 + (n - 1)(-7)

⇒ T_n = 26 -7n+1

⇒ T_n = 27 - 7n

<h3><u>Hence </u><u>the</u><u> </u><u>nth</u><u> </u><u>term</u><u> of</u><u> an</u><u> </u><u>AP</u><u> </u><u>can</u><u> </u><u>be</u><u> </u><u>found </u><u>using </u><u>T_</u><u>n</u><u> </u><u>=</u><u> </u><u>2</u><u>7</u><u> </u><u>-</u><u> </u><u>7</u><u>n</u><u>. </u></h3>

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Answer:

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Step-by-step explanation:

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\frac{dM}{dt}=0.1M-2400\\\\10\int \frac{dM}{M-24000} =\int dt\\\\10ln(M-24000)=t\\\\M-24000=Ce^{t/10}\\\\M=Ce^{t/10}+24000\\\\M(0)=Ce^{0/10}+24000=10000\\\\C+24000=10000\\\\C=-14000\\\\M(t)=24000-14000e^{t/10}

(b) We can calculate this as M(t)=0

M(t)=24000-14000e^{t/10}=0\\\\e^{t/10}=24000/14000=1.714\\\\t=10ln(1.714)=10* 0.5390=5.390

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