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3 years ago

Does the height of the shooter affect the number of goals scored in a netball match

Mathematics

2 answers:

Art [367]3 years ago

8 0

Answer:

Yes because a taller person would have a higher chance of getting the ball in the net

Step-by-step explanation:

Reil [10]3 years ago

5 0

It’s possible for a taller person to make a shot in the net then a short person because it will depend on they height.

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According to a Human Resources report, a worker in the industrial countries spends on average 419 minutes a day on the job. Supp

MA_775_DIABLO [31]

Answer:

A) Between 388 and 450

B) Between 357 and 481

C) Between 326 and 512

D) 99.995%

E) 72.907%

Step-by-step explanation:

We are given;

Mean; x¯ = 419 minutes

Standard deviation; σ = 31 minutes

A) From the empirical rule, 68% falls within 1 standard deviation.

Thus, it will be between;

419 - 1(31) and 419 + 1(31)

Thus gives;

Between 388 and 450

B) From the empirical rule, 95% falls within 2 standard deviation.

Thus, it will be between;

419 - 2(31) and 419 + 2(31)

Thus gives;

Between 357 and 481

C) From the empirical rule, 99.7% falls within 2 standard deviations.

Thus, it will be between;

419 - 3(31) and 419 + 3(31)

Thus;

Between 326 and 512

D)between 359 and 479 minutes, we will use z-s roe formula;

z = (479 - 359)/31

z = 3.871

From the z-table attached, we see that the probability is 0.99995 and as such, the percentage is 99.995%

E) worker spent 400 minutes on the job.

Thus;

z = (419 - 400)/31

z = 0.613

From z-tables, p = 0.72907

In percentage, we have; 72.907%

6 0

3 years ago

To solve problems about spans of time that include B.C. and A.D. dates, you would need to use which numbers?

Studentka2010 [4]

The correct numbers to use in solving problems about spans of time like B.C. and A.D. should be “integers”.

Integers are whole numbers (not a fractional number or not a decimal number) which can take a value of negative, zero, or positive number. Example of integers would be -1, 0 and 1.

<span>In calculations, the time period would be on the x-axis. Since B.C. and A.D. are two different spans of time, therefore in the calculations, the date of BC should be negative (negative x-axis) while the date of AD should be positive (positive x-axis). This would place the origin as the common reference.</span>

3 0

3 years ago

Which statements must be true regarding the diagram?<br> (please check more than one answer)

nikdorinn [45]

Try this option:
- true;
- not true;
- true;
- true;
- not true.

4 0

3 years ago

Read 2 more answers

Each car on a computer train holds 20 people. On a particular morning, 5 cars were 90% full and 3 cars were 65% full. If the peo

madam [21]

Answer:

7 cars

Step-by-step explanation:

The computation of the number of cars to be filled is shown below:

A car that is 90% full and the total people is 20 so 90% would be

= (.90)(20)

= 18

A car that is 65% full and the total people is 20 so 65% would be

= (.65)(20)

= 13

Now

Total number of people = (5)(18) + (3)(13).

= 129

Now the number of cars to be filled is

= 129 ÷ 20

= 6.45

= 7 cars

7 0

3 years ago

olice response time to an emergency call is the difference between the time the call is first received by the dispatcher and the

yan [13]

Answer:

0.7823 = 78.23% probability that the response time is between 3 and 9 minutes.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 7.2 minutes and a standard deviation of 2.1 minutes.

This means that $\mu = 7.2, \sigma = 2.1$