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yarga [219]
3 years ago
10

Find the slop of the line that passes Thur each pair of points

Mathematics
1 answer:
LuckyWell [14K]3 years ago
6 0

7 - -5 = 12  delta y
-3 - 4 = -7   delta x
12 divided by negative 7= the slope
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Write the following equation in slope-intercept form: 2x + 3y = 6
Leokris [45]

Answer:

y=-2/3x+2

Step-by-step explanation:

2x+3y=6

3y=6-2x

3y=-2x+6 /:3

y=-2/3x+6/3

y=-2/3x+2

Slope=-2/3

7 0
3 years ago
Read 2 more answers
NEED HELP FINDING SLOPE OF THE LINE
mamaluj [8]

Answer:

slope = - \frac{2}{3}

Step-by-step explanation:

calculate the slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 4, 2) and (x₂, y₂ ) = (2, - 2) ← 2 points on the line

m = \frac{-2-2}{2-(-4)} = \frac{-4}{2+4} = \frac{-4}{6} = - \frac{2}{3}

5 0
2 years ago
The price of a television in a certain store was a dollars in June. On the first day of each month after June, the price was red
Shtirlitz [24]

Answer:

0.8

Step-by-step explanation:

multiply 1.00 .20 4 times

6 0
2 years ago
A series of three? separate, adjacent tunnels is constructed through a mountain. Its length is approximately 25 kilometers. Each
Nadya [2.5K]

Answer:

312.5\pi \text{ km}^3\approx 981.75\text{ km}^3

Step-by-step explanation:

We have been given that a series of 3 separate, adjacent tunnels is constructed through a mountain. Its length is approximately 25 kilometers.

Each of the three tunnels is shaped like a half-cylinder with a radius of 5 meters.

Since we know that volume of a semicircular or a half cylinder is half the volume of a circular cylinder.

\text{Volume of a semicircular cylinder}=\frac{\pi r^2h}{2}, where,

r = Radius of cylinder,

h = height of the cylinder.

Upon substituting our given values in volume formula we will get,

\text{Volume of a semicircular cylinder}=\frac{\pi (5\text{ km})^2*25\text{ km}}{2}

\text{Volume of a semicircular cylinder}=\frac{\pi*25\text{ km}^2*25\text{ km}}{2}

\text{Volume of a semicircular cylinder}=\frac{\pi*625\text{ km}^3}{2}

\text{Volume of a semicircular cylinder}=\pi*312.5\text{ km}^3

\text{Volume of a semicircular cylinder}=\pi*312.5\text{ km}^3

\text{Volume of a semicircular cylinder}=981.74770\text{ km}^3

Therefore, the volume of earth removed to build the three tunnels is 312.5\pi \text{ km}^3\approx 981.75\text{ km}^3.


4 0
3 years ago
Sid brought $200 to the amusement park . the cost of admission is $16.25 , and the cost of a lunch is $6.50 . After Sid purchase
ra1l [238]
Let x represent the # of people in sid’s group: 200 - (16.25x + 6.50x) = 18.25
200 - 22.75x = 18.25
-22.75x = -181.75
x = about 8

if Sid is not included in the group, i think the answer is D. 7, but im not sure
5 0
3 years ago
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