Answer:
Since you didn't give me any choices I can tell you that c is ANY ODD NUMBER THAT EXISTS.
Step-by-step explanation:
im smart ツ
Answer:
Midpoint of a line segment
(xM,yM) = (4, 5).
Answer:
The function which represents this sequence will be:
![a_n=-15n+110](https://tex.z-dn.net/?f=a_n%3D-15n%2B110)
Hence, option (A) is true.
Step-by-step explanation:
Given the sequence
![95, 80, 65, 50, ...](https://tex.z-dn.net/?f=95%2C%2080%2C%2065%2C%2050%2C%20...)
An arithmetic sequence has a constant difference 'd' and is defined by
![a_n=a_1+\left(n-1\right)d](https://tex.z-dn.net/?f=a_n%3Da_1%2B%5Cleft%28n-1%5Cright%29d)
computing the differences of all the adjacent terms
![80-95=-15,\:\quad \:65-80=-15,\:\quad \:50-65=-15](https://tex.z-dn.net/?f=80-95%3D-15%2C%5C%3A%5Cquad%20%5C%3A65-80%3D-15%2C%5C%3A%5Cquad%20%5C%3A50-65%3D-15)
As the difference is the same, so
![d = -15](https://tex.z-dn.net/?f=d%20%3D%20-15)
as
![a_1=95](https://tex.z-dn.net/?f=a_1%3D95)
Thus, substituting
,
in the nth term of an arithmetic sequence
![a_n=a_1+\left(n-1\right)d](https://tex.z-dn.net/?f=a_n%3Da_1%2B%5Cleft%28n-1%5Cright%29d)
![a_n=-15\left(n-1\right)+95](https://tex.z-dn.net/?f=a_n%3D-15%5Cleft%28n-1%5Cright%29%2B95)
![a_n=-15n+110](https://tex.z-dn.net/?f=a_n%3D-15n%2B110)
Therefore, the function which represents this sequence will be:
![a_n=-15n+110](https://tex.z-dn.net/?f=a_n%3D-15n%2B110)
Hence, option (A) is true.
Answer:
formula is 6a²= surface area
but since one side is not being painted it is
5a²= surface area
5(3.2)²
=51.2cm
Answer:
If it is not raining, then I do not need my rain boots.
Step-by-step explanation:
idk the question is written a bit wrong, I don't know if I was able to switch the first statement. Sorry if I'm wrong!