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3 years ago

How would you solve the equation y-5=m(x-2)

1 answer:

7 0

One equation with 3 variables cannot be solved in the sense that you can find "the" 3 values for x, y and m. You can observe that this equation represents a family of straight lines with varying slope (depending on m).

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Anyone know the area of the blue area?

Studentka2010 [4]

First, find the area of the larger sector (the 360-130=230 degree sector), then add the area of the triangle.
area of the larger sector:(230/360)π*11.1²≈247.17
area of the triangle when two sides and the angle between the two sides are given: (absinФ)/2. In this case, a=11.1, b=11.1, Ф=130
(11.1*11.1*sin130)/2≈47.19
the total area is 247.17+47.19≈294.4
Please use your calculator to double check my numbers.

4 0

3 years ago

A right triangular prism has a height of 3 ft, a width of 4 ft, and a hypotenuse of 5 ft. The depth of the triangle is missing.

DiKsa [7]

Depth=15
x=(height(h)*width(w)*hypotenuse(y))/2
x=(3*4*5)/2=(60/2)=30
y=(x(x-h)(x-w)(x-y))^(1/2)
f=(-h^4+2(hw)^2+2(wy)^2-w^4+2(hy)^2-y^4)^(1/2)
f=(-3^4+2(3*4)^2+2(4*5)^2-4^4+2(3*5)^2-5^4)^(1/2)
f=576^(1/2)
f=24
Surface Area= 2f(.5)+(h+w+y)*depth
192=depth*(3+4+5)+24(.5)
180=(3+4+5)*depth
180=(12)(depth)
15=depth

8 0

3 years ago

#5 Antonio and Abby had the same nimber of paperclips. After Antonio gave 30 paperclips to Abby, Abby had twice as many papercli

Kay [80]

Answer:

#5: 180 paperclips in total.

#6: 126 stamps in total.

#7: Elena should give Lucy 15 colored pencils.

Step-by-step explanation:

This explanation solves each question by setting a single unknown, $x$ .

Let $x$ the initial number of paperclips of Antonio. That should also be the number of Abby's paperclips.

Initially:

Antonio: $x$ paperclips;
Abby: $x$ paperclips.

Antonio gives $30$ paperclips to Abby. After that,

Antonio: $(x - 30)$ paperclips;
Abby: $x + 30$ paperclips.

Abby now possess twice as many paperclips as Antonio does. In other words,

$2(x - 30) = x + 30$ .

By the distributive property:

$2x - 60 = x + 30$ .

Substract $x - 60$ from both sides

$x = 30 - (-60) = 90$ .

Both Antonio and Abby initially possess 90 paperclips. That's 180 in total.

Similarly, let $x$ be the number of Emily's stamps. That should be the same as the number of Jasmine's stamps.

Initially:

Emily: $x$ stamps;
Jasmine: $x$ stamps.

After Emily gives $42$ stamps to Jasmine:

Emily: $x-42$ stamps;
Jasmine: $x+42$ stamps.

Jasmine now possesses twice as many stamps as Emily does. In other words,

$2(x-42) = x+42$ .

$x = 42 + 2\times 42 = 126$ .

Jasmine used to possess 126 stamps. Now she possesses $126 + 42 = 168$ stamps after receiving $42$ stamps from Emily.

Let the number of pencils that Elena needs to give to Lucy be $x$ .

Initially:

Elena: 60 pencils;
Lucy: 26 pencils.

After Elena gives $x$ pencils to Lucy:

Elena: $60 - x$ pencils;
Lucy: $26 + x$ pencils.

Elena should now possess four more pencils than Lucy does. In other words,

$\underbrace{60 - x}_{\text{Elena's}} = \underbrace{(26 + x)}_{\text{Lucy's}} +4$ .

$2x = 30$ .

$x = 15$ .

8 0

2 years ago

Suppose the 13 inch is aware cost $.78 at the same rate how much (in cents) will 33 inches of wire cost

miskamm [114]

When comparing to thing with same rate, set up a proportion:
Inches/cost

13/.78=33/x
(13)(x)=(.78)(33) [cross multiplied]
13x=25.74 [simplified]
13/13x=25.74/13 [division property]
x=1.98

33 inches of wire will cost $1.98.

3 0

3 years ago

I have 12 coins x of them are R5 coins and the rest are R1 coins. An expression in the in terms of x for the number of R1 coins

Marrrta [24]

Answer:

ans= 12-x=r1 coin...

Step-by-step explanation:

hope u can do..

7 0

3 years ago